Let $M$ be a $d$-dimensional (say, Hausdorff, paracompact, connected and oriented) smooth manifold, and $K\subset M$ compact with $\mathring{K}\neq\varnothing$. M. Valdivia has shown (based on previous results by himself and D. Vogt, see e.g. M. Valdivia, A representation of the space $\mathscr{D}(K)$, J. reine angew. Math. 320 (1980) 97-98) that the nuclear Fréchet space $\mathscr{D}(K)$ of smooth functions supported in $K$ is topologically isomorphic to the space $s$ of rapidly decreasing sequences: $$s=\{(a_n)_{n\in\mathbb{N}}\ |\ ((1+n)^k a_n)_{n\in\mathbb{N}}\text{ is bounded for all }k\in\mathbb{N}\}\ .$$ Let $\Phi:\mathscr{D}(K)\cong s$ denote a Valdivia-Vogt isomorphism (see Edit below). It is clear that the transpose ${}^t\Phi$ of $\Phi$ yields a topological isomorphism between the dual $s'$ of $s$ $$s'=\{(a_n)_{n\in\mathbb{N}}\ |\ ((1+n)^{-k}a_n)_{n\in\mathbb{N}}\text{ is bounded for some }k\in\mathbb{N}\}$$ and the dual $\mathscr{D}(K)'$ of $\mathscr{D}(K)$, which may be identified as a vector space with $\mathscr{D}'(\wedge^d T^*M\rightarrow M)/\mathscr{D}(K)^\perp$, where $$\mathscr{D}(K)^\perp=\{u\in\mathscr{D}'(\wedge^d T^*M\rightarrow M)\ |\ u(\varphi)=0\text{ for all }\varphi\in\mathscr{D}(K)\}$$ is the annihilator of $\mathscr{D}(K)$. It is clear that $\mathscr{D}(K)'$ contains $$\mathscr{E}'(K)=\{u\in\mathscr{E}'(\wedge^d T^*M\rightarrow M)\ |\ \text{supp }u\subset K\}$$ as a (closed) subspace (I apologize for the slightly unconventional notation). Since the sequences $e_j=(e_{j,n})_{n\in\mathbb{N}}$ given by $$e_{j,n}=\begin{cases} 0 & (n\neq j) \\ 1 & (n=j) \end{cases}$$ form a Schauder basis of both $s$ and $s'$, it is clear that $s$ is dense in $s'$.
Question: Is there a choice of $\Phi$ (see Edit below) such that it extends to a topological isomorphism between $\mathscr{E}'(K)$ and $s'$? Likewise, does the restriction of ${}^t\Phi$ to $s$ for such a $\Phi$ yield another topological isomorphism between $s$ and $\mathscr{D}(K)$?
My question is inspired by the known characterization of $\mathscr{D}([0,1])$ and $\mathscr{E}'([0,1])$ through the decay / growth of their Fourier coefficients in $[0,1]$.
Edit: As suggested by Jochen Wengenroth in the comments below, the recent works of Bargetz
- C. Bargetz, Commutativity of the Valdivia-Vogt table of representations of function spaces. Math. Nachr. 287 (2014) 10-22
- C. Bargetz, Explicit representations of spaces of smooth functions and distributions, J. Math. Anal. Appl. 424 (2015) 1491-1505
- C. Bargetz, Completing the Valdivia-Vogt tables of sequence-space representations of spaces of smooth functions and distributions. Monatsh. Math. 177 (2015) 1-14
indicate that the answer to the question may be negative depending on the choice of Valdivia-Vogt isomorphism $\Phi$. More precisely, one needs first for ${}^t\Phi$ to map $\{e_j\ |\ j\in\mathbb{N}\}$ into $\mathscr{D}(K)$, which may not be the case.