Two coupled nonlinear differential equations in a radial $r$direction in the region $r \in [0, \infty)$:
$$ a\big(\partial_r^2+\frac{\partial_r}{r}\frac{n^2}{r^2}+c\big) U(r)+ B(r) (\partial_r\frac{n}{r}\big) V(r)=n\; k \; U(r) $$ $$ B(r) (\partial_r+\frac{n}{r}\big) U(r) + a\big(\partial_r^2+\frac{\partial_r}{r}\frac{n^2}{r^2}+c\big) V(r) =n\; k \; V(r), $$ We like to solve $U(r)$ and $V(r)$ (say, better analytically and exactly). What are the exact solutions of $U(r)$ and $V(r)$? (or approximate solutions?)
This is a more general set of equations extending from the post here
Here are the conditions of $B(r),a,c,k$.
The B(r) is given such that $B(r)$ is a nice smooth differentiable function, with $$B(0)=0$$ $$\lim_{r \to 0} B(r)=0$$ $$\lim_{r \to \infty} B(r)=b=\text{constant} >0,$$ and $B(r) \geq 0$ is monotonically increasing along $r \in [0, \infty)$, also $$a=\text{constant} >0.$$ $$c=\text{constant} \geq 0.$$
$$n \in \mathbb{Z}^+=\text{integer natural number constant} >0.$$
$$k=\text{constant} >0.$$ For your convenience, here $k$ can be chosen of our convenience such that the equations can be solved more easily. My suggestion and trial finds that $$ k=\frac{b^2 }{a\; c} $$ or at least the leading order $$ k=\frac{b^2 }{a\; c} + \cdots $$ look more promising for exact solutions.
Both $a$, $b$ and $c$ are finite values.
I have done some analysis myself. My expected analysis find that $U(r)$ and $V(r)$ have exponential decay tails that look like $$\exp[\int_0^r B(r')^{\#} dr']$$ The ${\#}$ means some tentative power. And both $U(r)$ and $V(r)$ likely contain Bessel functions $J_0(r),J_1(r), ...,etc$.
I suppose that their positivevalued peaks are localized near $r=0$, but oscillating modes along $r$, where $U(0)$ and $V(0)$ are nearly in their maximum, with exponential decay tails $\lim_{r \to 0} U(r)=\lim_{r \to 0} V(r)=0.$ But I could be wrong.
If exact analytic solutions are NOT possible, please give arguments, and please feel free to take approximations. Personally, I believe that it can be solved analytically exactly by some Bessel type functions.
It will be OK, for your answer, just for focus on the simple cases that $n=1$ or $n=2$. Even though one may consider generic $n \in \mathbb{Z}^+$ in general, but it is not necessary.

The special cases of my questions boil down to here and here.
(p.s. This is some fun trial analysis done by myself.)