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Let $K\subseteq \mathbb{R} ^n$ be closed and convex, and let $F:K \to \mathbb R^n $ be a continuous function. If for every $x,y \in K$ we have $$(x-y)^T(F(x)-F(y))\ge \alpha ||x-y||^2 \, ;\quad \alpha\gt0 \, ,$$we want to prove that there exist a unique $x^*$ such that $F(x^*)^T(x-x^*)\ge 0$ for all $x\in K$.

The uniqueness proof is obvious. Assuming there are two answers we have $(x^*-x')^T(F(x')-F(x^*))\ge\alpha ||x^*-x'||^2$ Which is a contradiction.

But how to prove that there exists answer?

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    $\begingroup$ Can you provide a title more specifically related to the contents of the question`, $\endgroup$
    – YCor
    Commented Dec 30, 2016 at 7:54
  • $\begingroup$ Also, I've tried to edit, but I didn't understand your uniqueness proof. (a) Who's $y$? (b) Why is this a contradiction? $\endgroup$
    – Amir Sagiv
    Commented Dec 30, 2016 at 8:23
  • $\begingroup$ Your condition on $F$ implies that it is strongly monotone. Check Showalter's book on nonlinear equation in Banach spaces for an answer. $\endgroup$
    – Dirk
    Commented Dec 31, 2016 at 0:28

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