Let $q=e^{2\pi it}$. If $u(t)$ is Ramanujan's octic continued fraction, is it true that the generator of the octahedral group can be expressed as a continued fraction of the form $$ (u(2t))^2=\frac{2q^{1/2}}{1-q+\frac{q(1+q)^2}{1-q^3+\frac{q^2(1+q^2)^2}{1-q^5+\frac{q^3(1+q^3)^2}{1-q^7+\ldots}}}} $$ for $|q|\lt 1$?
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1$\begingroup$ I think I didn't mess things up when adding formatting. In any case, it doesn't look ridiculously wrong. $\endgroup$– David Roberts ♦Commented Jul 8, 2015 at 7:29
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2$\begingroup$ Some motivation would be nice. $\endgroup$– Jim ConantCommented Jul 8, 2015 at 7:56
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