Let $q=e^{2\pi it}$. If $u(t)$ is Ramanujan's octic continued fraction, is it true that the generator of the octahedral group can be expressed as a continued fraction of the form $$ (u(2t))^2=\frac{2q^{1/2}}{1q+\frac{q(1+q)^2}{1q^3+\frac{q^2(1+q^2)^2}{1q^5+\frac{q^3(1+q^3)^2}{1q^7+\ldots}}}} $$ for $q\lt 1$?
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1$\begingroup$ I think I didn't mess things up when adding formatting. In any case, it doesn't look ridiculously wrong. $\endgroup$ – David Roberts Jul 8 '15 at 7:29

2$\begingroup$ Some motivation would be nice. $\endgroup$ – Jim Conant Jul 8 '15 at 7:56