0
$\begingroup$

$A$ belongs to $n$-dimensional quaternion symmetric matrix, in the sense that $A=A^T$, where $T$ means transpose. Under transformation $U$, $A\rightarrow U\cdot A\cdot U^T$, where $U$ is $n$-dim unitary quaternion matrix, namely $U\in\mathrm{Sp}(n)$.

Then, my question is, what is the canonical form of $A$? Can we diagonalize $A$ using the above transformation such that all entries are real? What about the case that $A$ is skew-symmetric quaternion matrix? Thanks!

$\endgroup$
2
  • $\begingroup$ In both cases it works exactly as over $\mathbf C$. $\endgroup$
    – few_reps
    Commented Dec 16, 2014 at 6:49
  • $\begingroup$ Thanks very much, @few_reps! Do you have any reference? $\endgroup$ Commented Dec 16, 2014 at 14:48

0

You must log in to answer this question.

Browse other questions tagged .