Let $X_1,\ldots,X_n$ be independent with $\mathbf{E}[X_i] = 0$ and $\mathbf{E}[|X_i|^t] < \infty$ for some $t \ge 2$. Write $X = \sum_{i=1}^n X_i$. Then we have the family of "Rosenthal-type inequalities":
$$ \mathbf{E}[|X|^t] \le C_1(t)\cdot \left(\sum_{i=1}^n \mathbf{E}[|X_i|^t]\right) + C_2(t)\cdot \left(\sum_{i=1}^n \mathbf{E}[X_i^2]\right)^{t/2} .$$
Henceforth, $c>0$ is some absolute constant. I have seen in various papers that we can, for example, take $C_1(t) = C_2(t) = (ct/\log(t))^t$. We can also take $C_1(t) = (ct)^t, C_2(t) = (c\sqrt{t})^t$. Another option is $C_1(t) = c^t, C_2(t) = c^t\cdot 2^{t^2/4}$.
Is it known whether there is some non-trivial tradeoff curve for the relationship between $C_1(t)$ and $C_2(t)$? For example, if I'm fine with setting $C_2(t) = (ct^{2/3})^t$, what's the best $C_1(t)$ I can get?
\sqrt{t}
constant? Thanks! $\endgroup$