I was recently reminded of the following cute fact which I will state as a proposition to fix notation:
Proposition Given $\epsilon > 0$, let $c = -3/4 + \epsilon i \in \mathbb{C}$ and $q_c(z) = z^2 + c$. Define the sequence of polynomials $q_c^n$ inductively by $q_c^0(z) = z$ and $$ q_c^{n+1}(z) = q_c(q_c^n(z)). $$ Since $q_c^n(0) \to \infty$ as $n \to \infty$, $$ N(\epsilon) = \min\{n ~:~ |q_c^n(0)| > 2 \} $$ is well-defined. The cute fact is that: $$ \epsilon N(\epsilon) \to \pi, $$ as $\epsilon \to 0$.
The next-simplest example of this phenomenon uses $c = 1/4 + \epsilon$. If we define $N(\epsilon)$ similarly then this time it turns out that: $$ \sqrt{\epsilon} N(\epsilon) \to \pi, $$ as $\epsilon \to 0$.
The points $-3/4$ and $1/4$ are the "neck" and "butt", respectively, of the Mandelbrot set and there are various other examples of these "$\pi$ paths": they are suitably-parameterised curves simultaneously tangent to two bulbs of the Mandelbrot set where they meet it. In fact I'd guess any part of the boundary where a bulb bubbles off works and so there are infinitely many such paths. External rays seem the obvious paths and they have a natural parameterisation. (Note that although $\epsilon \mapsto -3/4 + \epsilon i$ is not an external ray, it is asymptotic to one, as least set-wise, which is really all that matters.)
If true, I'm sure this is all in the literature (perhaps implicitly) but I don't know the field and after of searching through some lovely papers I couldn't find what I wanted. A naive guess is that something like the following might be true:
Half-serious conjecture Let $M \subset \mathbb{C}$ be the Mandelbrot set, $\overline D \subset \mathbb{C}$ the closed unit disc and $\Phi : \mathbb{C} - M \to \mathbb{C} - \overline D$ the unique conformal isomorphism such that $\Phi(c) \sim c$ as $c \to \infty$. Let $e^{i\theta} \in S^1$ (for $\theta$ rational) and let: $$ \alpha : (1, \infty) \to \mathbb{C} - M\\ r \mapsto \Phi^{-1}(re^{i\theta}) $$ Let $c = \alpha(r)$ and define $N(r)$ as above, then: $$ N(r) \sim \pi / f_\theta(r) $$ for some function $f_\theta$, such that $f_\theta(r) \to 0$ as $r \to 1$ and in particular $f_0(r) \sim \sqrt{\alpha(r)-1/4}$ and $f_{1/3} \sim -i(\alpha(r)+3/4)$.
Here then, at last, is my question:
Question Is some suitably-modified form of the above conjecture correct and is there a proof in the literature toward which somebody could direct me?
Aside from general curiosity my motivation stems from the fact that it's not too hard to prove the stated results for the $c = -3/4 + \epsilon i$ and $c = 1/4 + \epsilon$ paths separately but I'd like to have a unified proof. E.g., to prove the result for the (easier) $c = 1/4 + \epsilon$ path we consider: $$ z_{n+1} = z_n^2 + 1/4 + \epsilon\\ \Rightarrow z_{n+1} - z_n = (z_n - 1/2)^2 + \epsilon $$ Then approximate: $$ \frac{dz}{dn} \simeq (z-1/2)^2 + \epsilon\\ \Rightarrow z(n) = 1/2 + \sqrt{\epsilon}\tan(\sqrt{\epsilon}n)\\ \Rightarrow \sqrt{\epsilon}N(\epsilon) \simeq \tan^{-1}(\frac{3}{2\sqrt{\epsilon}} ) - \tan^{-1}(-\frac{1}{2\sqrt{\epsilon}}) $$ And so provided we can justify the approximation is accurate as $\epsilon \to 0$ (which is tricky but possible) the result follows.