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kodlu
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One question on circulant $(-1,1)$-matrices$\pm1$ matrices

Let $n > 13$ be a positive integer. Is there any $n\times n$$n \times n$ circulant $(-1,1)$-matrix$\pm1$ matrix $A$ satisfying the following property:

$$AA^T=(n-1)I+J$$

where $I$ is the $n\times n$$n \times n$ identity matrix and $J$ is the $n\times n$ matrix of ones.?

I conjecture that the answer is no. But I can't prove it.

One question on circulant $(-1,1)$-matrices

Let $n > 13$ be a positive integer. Is there any $n\times n$ circulant $(-1,1)$-matrix $A$ satisfying the following property:

$$AA^T=(n-1)I+J$$

where $I$ is the $n\times n$ identity matrix and $J$ is the $n\times n$ matrix of ones.

I conjecture that the answer is no. But I can't prove it.

One question on circulant $\pm1$ matrices

Let $n > 13$ be a positive integer. Is there any $n \times n$ circulant $\pm1$ matrix $A$ satisfying the following property

$$AA^T=(n-1)I+J$$

where $I$ is the $n \times n$ identity matrix and $J$ is the $n\times n$ matrix of ones?

I conjecture that the answer is no. But I can't prove it.

The answer is yes for $n=13$.
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user369335
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Let $n\ge13$$n > 13$ be a positive integer. Is there any $n\times n$ circulant $(-1,1)$-matrix $A$ satisfying the following property:

$$AA^T=(n-1)I+J$$

where $I$ is the $n\times n$ identity matrix and $J$ is the $n\times n$ matrix of ones.

I conjecture that the answer is no. But I can't prove it.

Let $n\ge13$ be a positive integer. Is there any $n\times n$ circulant $(-1,1)$-matrix $A$ satisfying the following property:

$$AA^T=(n-1)I+J$$

where $I$ is the $n\times n$ identity matrix and $J$ is the $n\times n$ matrix of ones.

I conjecture that the answer is no. But I can't prove it.

Let $n > 13$ be a positive integer. Is there any $n\times n$ circulant $(-1,1)$-matrix $A$ satisfying the following property:

$$AA^T=(n-1)I+J$$

where $I$ is the $n\times n$ identity matrix and $J$ is the $n\times n$ matrix of ones.

I conjecture that the answer is no. But I can't prove it.

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Denis Serre
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user369335
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