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I've added explicitely the definition of radical of an integer as companion of the linked Wikipedia, see also A007947 from the OEIS. Added the tags (inequality) and (analytic-number-theory).
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Let $P(n)$ be the statement that $$n < \mathrm{rad}(n(n-1)(n-2)),$$ where $\mathrm{rad}$ is the radical of an integer, that is defined as $$\operatorname{rad}(m)=\prod_{\substack{p\mid m\\p\text{ prime}}}p$$ for integers $m>1$ with $\operatorname{rad}(1)=1$.

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$.

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

Let $P(n)$ be the statement that $$n < \mathrm{rad}(n(n-1)(n-2)),$$ where $\mathrm{rad}$ is the radical of an integer.

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$.

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

Let $P(n)$ be the statement that $$n < \mathrm{rad}(n(n-1)(n-2)),$$ where $\mathrm{rad}$ is the radical of an integer, that is defined as $$\operatorname{rad}(m)=\prod_{\substack{p\mid m\\p\text{ prime}}}p$$ for integers $m>1$ with $\operatorname{rad}(1)=1$.

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$.

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

formatting, removed duplicate
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Is it a known property of positive integers $n> 2 $ that one must have $n < rad\mathrm{rad}(n(n-1)(n-2))$?

Let $P(n)$ be the statement that $n < rad(n(n-1)(n-2))$ $$n < \mathrm{rad}(n(n-1)(n-2)),$$ where $\mathrm{rad}$ is the radical of an integer.

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$: $$n < rad(n(n-1)(n-2))$$.

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

Rad is the radical of an integer

Is it a known property of positive integers $n> 2 $ that one must have $n < rad(n(n-1)(n-2))$?

Let $P(n)$ be the statement that $n < rad(n(n-1)(n-2))$

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$: $$n < rad(n(n-1)(n-2))$$

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

Rad is the radical of an integer

Is it a known property of positive integers $n> 2 $ that one must have $n < \mathrm{rad}(n(n-1)(n-2))$?

Let $P(n)$ be the statement that $$n < \mathrm{rad}(n(n-1)(n-2)),$$ where $\mathrm{rad}$ is the radical of an integer.

I checked that $P(n)$ holds for $3 \le n \le 3.10^7$.

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

clean up phrasing. Based on tag also adding explicit question about if previously conjectured.
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Is it a newknown property of positive integer numberintegers $n> 2 $ that one must have $n < rad(n(n-1)(n-2))$?

Is it a new property of positive integer numberLet $P(n)$ be the statement that $n < rad(n(n-1)(n-2))$

I checked the as follows propertiesthat $P(n)$ holds for   $3 \le n \le 3.10^7$: $$n < rad(n(n-1)(n-2))$$

My question: Is the property$P(n)$ true for any positive integer number$n \geq 3$?

Also, is this a pre-existing conjecture?

Rad is the radical of an integer

Is it a new property of positive integer number $n < rad(n(n-1)(n-2))$?

Is it a new property of positive integer number $n < rad(n(n-1)(n-2))$

I checked the as follows properties holds for $3 \le n \le 3.10^7$: $$n < rad(n(n-1)(n-2))$$

My question: Is the property true for any positive integer number?

Rad is the radical of an integer

Is it a known property of positive integers $n> 2 $ that one must have $n < rad(n(n-1)(n-2))$?

Let $P(n)$ be the statement that $n < rad(n(n-1)(n-2))$

I checked that $P(n)$ holds for   $3 \le n \le 3.10^7$: $$n < rad(n(n-1)(n-2))$$

My question: Is $P(n)$ true for any positive integer $n \geq 3$?

Also, is this a pre-existing conjecture?

Rad is the radical of an integer

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