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Post Reopened by Alex Degtyarev, Joonas Ilmavirta, Stefan Kohl, Ricardo Andrade, Felipe Voloch
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Factoring Find all possible rational values of the parameter of a parametric cubic as a rational linear times an irreducible quadraticsuch that it is reducible

Description: Given the following parametric cubic pairpolynomials ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, whathow do I find all possible rational values of the parameter $\eta$ will factorsuch that this cubic into a rational linear times an irreducible quadraticpolynomial is reducible.

Background: I am studying the Galois classification of an infinite familyhave found 61 rational values of parametric polynomials and their reducible cases. The main variable is $E$ (energy) and the parameter $\eta$ or $\zeta = {\eta}^{2}$ is the asymmetry parameter. The above cubic has a sextic discriminant in parameter $\eta$. Using the online version of MAGMA I can verify that the cases where this cubic fully factors over $\mathbb{Q}$ are $\eta \in \left\{{0,-3, +3}\right\}$ forfactor these polynomials into a rational $\eta = p/q$ forlinear $|p|, q \le {10}^{6}$. Solving this cubic$E - p/q$ for the parameter $\eta$ also results in a cubic in $E$. Rational searches have identifiedinteger $61$ points so far that reduce this cubic$p$ and ($p \in \left[{-{10}^{5},+{10}^{5}}\right]$$q$ relatively prime and $q \in \left[{1, 30{,}000}\right]$). In other cubic cases I can derive$q \ne 0$ times an elliptic curve condition that results in infinite setirreducible quadratic of points that factor the cubic by arithmetic on the elliptic generator points. So far for this case I have not been able to identify any elliptic curve relations that would enable me to automatically generate the points and which also verifies that the number of such points is infinite.

Synthetic division of a rational linear leaves a quadraticform ${E}^{2} + a\, E + b$. However, this does I do not generate any additional information or conditions.

Summary: Isknow if there are an infinite number of rational points that factor this cubic pairsuch values and if so hownot do I generate these points. Equivalently for some rational $E$ there corresponds a rational $\eta$ and vis versa. Find a way to generate and enumerate these rational pair setshave the complete set.

Factoring parametric cubic as a rational linear times an irreducible quadratic

Description: Given the following parametric cubic pair ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, what rational values of the parameter $\eta$ will factor this cubic into a rational linear times an irreducible quadratic.

Background: I am studying the Galois classification of an infinite family of parametric polynomials and their reducible cases. The main variable is $E$ (energy) and the parameter $\eta$ or $\zeta = {\eta}^{2}$ is the asymmetry parameter. The above cubic has a sextic discriminant in parameter $\eta$. Using the online version of MAGMA I can verify that the cases where this cubic fully factors over $\mathbb{Q}$ are $\eta \in \left\{{0,-3, +3}\right\}$ for rational $\eta = p/q$ for $|p|, q \le {10}^{6}$. Solving this cubic for the parameter $\eta$ also results in a cubic in $E$. Rational searches have identified $61$ points so far that reduce this cubic ($p \in \left[{-{10}^{5},+{10}^{5}}\right]$ and $q \in \left[{1, 30{,}000}\right]$). In other cubic cases I can derive an elliptic curve condition that results in infinite set of points that factor the cubic by arithmetic on the elliptic generator points. So far for this case I have not been able to identify any elliptic curve relations that would enable me to automatically generate the points and which also verifies that the number of such points is infinite.

Synthetic division of a rational linear leaves a quadratic. However, this does not generate any additional information or conditions.

Summary: Is there an infinite number of rational points that factor this cubic pair and if so how do I generate these points. Equivalently for some rational $E$ there corresponds a rational $\eta$ and vis versa. Find a way to generate and enumerate these rational pair sets.

Find all possible rational values of the parameter of a parametric cubic such that it is reducible

Description: Given the following parametric cubic polynomials ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, how do I find all possible rational values of $\eta$ such that this polynomial is reducible.

Background: I have found 61 rational values of $\eta$ that factor these polynomials into a rational linear $E - p/q$ for integer $p$ and $q$ relatively prime and $q \ne 0$ times an irreducible quadratic of the form ${E}^{2} + a\, E + b$. I do not know if there are an infinite number of such values and if not do I have the complete set.

Post Closed as "Needs details or clarity" by Daniel Loughran, Stefan Kohl, Joonas Ilmavirta, Alex Degtyarev, Ricardo Andrade
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Description: Given the following parametric cubic pair ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, what rational values of the parameter $\eta$ will factor this cubic into a rational linear times an irreducible quadratic.

Background: I am studying the Galois classification of an infinite family of parametric polynomials and their reducible cases. The main variable is $E$ (energy) and the parameter $\eta$ or $\zeta = {\eta}^{2}$ is the asymmetry parameter. The above cubic has a sextic discriminant in parameter $\eta$. Using the online version of MAGMA I can verify that the cases where this cubic fully factors over $\mathbb{Q}$ are $\eta \in \left\{{0,-3, +3}\right\}$ for rational $\eta = p/q$ for $|p|, q \le {10}^{6}$. Solving this cubic for the parameter $\eta$ also results in a cubic in $E$. Rational searches have identified $61$ points so far that reduce this cubic ($p \in \left[{-{10}^{5},+{10}^{5}}\right]$ and $q \in \left[{1, 29{,}000}\right]$$q \in \left[{1, 30{,}000}\right]$). In other cubic cases I can derive an elliptic curve condition that results in infinite set of points that factor the cubic by arithmetic on the elliptic generator points. So far for this case I have not been able to identify any elliptic curve relations that would enable me to automatically generate the points and which also verifies that the number of such points is infinite.

Synthetic division of a rational linear leaves a quadratic. However, this does not generate any additional information or conditions.

Summary: Is there an infinite number of rational points that factor this cubic pair and if so how do I generate these points. Equivalently for some rational $E$ there corresponds a rational $\eta$ and vis versa. Find a way to generate and enumerate these rational pair sets.

Description: Given the following parametric cubic pair ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, what rational values of the parameter $\eta$ will factor this cubic into a rational linear times an irreducible quadratic.

Background: I am studying the Galois classification of an infinite family of parametric polynomials and their reducible cases. The main variable is $E$ (energy) and the parameter $\eta$ or $\zeta = {\eta}^{2}$ is the asymmetry parameter. The above cubic has a sextic discriminant in parameter $\eta$. Using the online version of MAGMA I can verify that the cases where this cubic fully factors over $\mathbb{Q}$ are $\eta \in \left\{{0,-3, +3}\right\}$ for rational $\eta = p/q$ for $|p|, q \le {10}^{6}$. Solving this cubic for the parameter $\eta$ also results in a cubic in $E$. Rational searches have identified $61$ points so far that reduce this cubic ($p \in \left[{-{10}^{5},+{10}^{5}}\right]$ and $q \in \left[{1, 29{,}000}\right]$). In other cubic cases I can derive an elliptic curve condition that results in infinite set of points that factor the cubic by arithmetic on the elliptic generator points. So far for this case I have not been able to identify any elliptic curve relations that would enable me to automatically generate the points and which also verifies that the number of such points is infinite.

Summary: Is there an infinite number of rational points that factor this cubic pair and if so how do I generate these points. Equivalently for some rational $E$ there corresponds a rational $\eta$ and vis versa. Find a way to generate and enumerate these rational pair sets.

Description: Given the following parametric cubic pair ${E}^{3} - 15\, {\beta}_{\pm}\, {E}^{2} - 3 \left({71\, {\beta}_{\pm}^{2} + 352\, {\beta}_{\mp}}\right) E + 135\, {\beta}_{\pm} \left({5\, {\beta}_{\pm}^{2} - 32\, {\beta}_{\mp}}\right)$ where ${\beta}_{\pm} = 1 \pm \eta$, what rational values of the parameter $\eta$ will factor this cubic into a rational linear times an irreducible quadratic.

Background: I am studying the Galois classification of an infinite family of parametric polynomials and their reducible cases. The main variable is $E$ (energy) and the parameter $\eta$ or $\zeta = {\eta}^{2}$ is the asymmetry parameter. The above cubic has a sextic discriminant in parameter $\eta$. Using the online version of MAGMA I can verify that the cases where this cubic fully factors over $\mathbb{Q}$ are $\eta \in \left\{{0,-3, +3}\right\}$ for rational $\eta = p/q$ for $|p|, q \le {10}^{6}$. Solving this cubic for the parameter $\eta$ also results in a cubic in $E$. Rational searches have identified $61$ points so far that reduce this cubic ($p \in \left[{-{10}^{5},+{10}^{5}}\right]$ and $q \in \left[{1, 30{,}000}\right]$). In other cubic cases I can derive an elliptic curve condition that results in infinite set of points that factor the cubic by arithmetic on the elliptic generator points. So far for this case I have not been able to identify any elliptic curve relations that would enable me to automatically generate the points and which also verifies that the number of such points is infinite.

Synthetic division of a rational linear leaves a quadratic. However, this does not generate any additional information or conditions.

Summary: Is there an infinite number of rational points that factor this cubic pair and if so how do I generate these points. Equivalently for some rational $E$ there corresponds a rational $\eta$ and vis versa. Find a way to generate and enumerate these rational pair sets.

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