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10 votes
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Upper bound total variation by Wasserstein distance for continuous distance

No. One should realize that the transportation and the total variation distances metrize two quite different topologies. Even if the measures are equivalent (i.e., absolutely continuous with respect ...
R W's user avatar
  • 17k
9 votes

Proving the inequality involving Hausdorff distance and Wasserstein infinity distance

EDIT: answer 2 below is completely false, as pointed out by the OP. However this is such a typical example of wishful thinking that I believe it is worth leaving for the posterity. (I'll record it ...
leo monsaingeon's user avatar
7 votes
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Is the following set compact w.r.t. the Wasserstein distance?

Unfortunately not. Take $q = \delta_0$ and $p_n = (1-n^{-1})\delta_0 + n^{-1}\delta_n$. Then $p_n \in A$ (with say $K = M = R = 1$) and $p_n \to \delta_0$ weakly but not in $\mathcal{P}_1$...
Martin Hairer's user avatar
6 votes
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Perturbation of Wasserstein distance: looking for references

You can find this in Villani's "small book", Theorem 8.13 in [Villani, C. (2003). Topics in optimal transportation (Vol. 58). American Mathematical Soc.] I can also recommend looking at ...
leo monsaingeon's user avatar
5 votes

1-Wasserstein distance between two multivariate normal

For $p=1$ one can bound the 1-Wasserstein metric by $$|m-n| + \sqrt{\sum_{i=1}^{d} \left[ \left( \sqrt{\lambda_i} - \sqrt{\gamma_i}\right)^2 + 2\sqrt{\lambda_i\gamma_i}(1-v_i\cdot u_i) \right]}$$ ...
Meni's user avatar
  • 203
5 votes

Upper bound total variation by Wasserstein distance for continuous distance

If both probability measures have smooth densities, the total variation can be bounded by Wasserstein (even by a weaker metric Levy-Prokhorov), see the 2017 paper A novel approach to Bayesian ...
Minwoo Chae's user avatar
5 votes
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Gradient of Wasserstein distance in the sense of Otto's calculus

Yes this is true, formally this follows by the envelope theorem. In an abstract and very smooth setting, the envelope theorem says that for an objective functional depending on a parameter $t$ $$ F(t)=...
leo monsaingeon's user avatar
5 votes
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Wasserstein distance and put function

$\newcommand\R{\Bbb R}\newcommand\LS{\mathsf{LS}}$For real $x$ and $y$ such that $x<y$, $$\begin{aligned} P_\mu(y)-P_\mu(x)&=\int_\R[(y-t)_+-(x-t)_+]\mu(dt) \\ &=\int_\R[(y-x)\,1(t\le x)+(...
Iosif Pinelis's user avatar
4 votes
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Wasserstein distance between product measures

$\newcommand{\de}{\delta}\renewcommand{\S}{\mathcal S}\newcommand{\T}{\mathcal T}$The answer to your question is negative if $p<2$. Indeed, let $\nu_i=\de_0$ for all $i$, where $\de_a$ is the Dirac ...
Iosif Pinelis's user avatar
4 votes
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2-Wasserstein metric on convolution of probability distributions

The answer is yes to the second question, and hence yes to the first question as well. Indeed, it is easy to check that the functions $f$ and $g$ given by $$f(t):=\max(0,1-|t|)$$ and $$g(t):=\sum_{k=-\...
Iosif Pinelis's user avatar
4 votes
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Does complete and separable Wasserstein space imply a complete base space?

$\newcommand\de\delta\newcommand\ep\varepsilon$The conjecture is true. Indeed, let $(z_n)$ be a Cauchy-convergent sequence in $(Z,d)$. Then $$d_{W_p}(\de_{z_m},\de_{z_n})=d(z_m,z_n)\to0$$ (as $m,n\to\...
Iosif Pinelis's user avatar
4 votes
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Compactness with respect to topology induced by total-variation distance

$\newcommand\vpi\varphi\newcommand\ep\varepsilon\newcommand\R{\Bbb R}$What you "need to show" is of course false in general. E.g., suppose that $d=1$ and $\varphi=1_{[0,1]}$. Then your set ...
Iosif Pinelis's user avatar
3 votes
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Is there $\varepsilon \in (0, 1)$ such that $\sup_{t \in [0, \varepsilon]} [\ell_t]_\beta < \infty$?

Pick a sequence of functions $g_n$ where (i) $\|g_n\|_\beta=n$ and (ii) $\|g_n-\mathbf 1\|_\infty\le 3^{-n}$. For example $$ g_n(x)=\begin{cases} 1+n(a_n-x)^\beta&\text{if $0\le x\le a_n$};\\ 1&...
Anthony Quas's user avatar
  • 23.2k
3 votes

Wasserstein distance between product measures

From the previous answer, it follows that the inequality is true when $p\ge 2$. Let $X_i, Y_i$ be the optimal choice of random variables for which $$\|X_i-Y_i\|_p=W_p(\mu_i,\nu_i) \ \forall i=1,\ldots,...
Ribhu's user avatar
  • 407
3 votes

An inequality involving the Wasserstein distance and chi-squared distance

$\newcommand{\N}{\mathbb N}$By the known expression for the Wasserstein distance, \begin{equation*} \begin{aligned} W_1(p,q)&=\int_0^\infty dx\,\Big|\sum_{n>x}(p_n-q_n)\Big| \\ &\...
Iosif Pinelis's user avatar
3 votes
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The uniqueness of Barycenters in the Wasserstein space

Uniqueness follows directly from proposition 3.3 on the previous page. For completeness, a shortened version containing the relevant parts: Suppose $\mu$ and $\nu$ are probability measures on $\...
Gabriel Clara's user avatar
3 votes
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Is this set $\sigma$-compact in the Wasserstein space?

It seems $A$ is not $\sigma$-compact. Check my argument as I have never worked with Wasserstein distances. Let $d=1$, let $q$ be the measure supported in $\{0\}$, so that $W_1(q,\mu)=\int|x|d\mu$ for ...
Saúl RM's user avatar
  • 10.6k
2 votes

Upper bound total variation by Wasserstein distance for continuous distance

To complement the existing answers, the following example shows that a bound $$ \|\mu - \nu\|_{1} ≤ C W_2(\mu, \nu) \tag{1} $$ does not hold even when we restrict the densities to smooth, globally ...
Rastapopoulos's user avatar
2 votes
Accepted

Bounding $2$-Wasserstein distance and the $L^1$ distance

Referring to the proof of Prop 3.21 in Malrieu 2001, after the triangle inequality is applied twice, two of the terms are bounded via the upper bound $$ W_2(u_t,u_t^{(1,N)}) \vee W_2(\mu_{1,N},\bar{u})...
Nawaf Bou-Rabee's user avatar
2 votes
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Getting Wasserstein closeness from a derivative estimate

Assuming the support of both measures is fixed, it is enough to bound $W_1(\mu,\nu)$. That is, we want to bound $\vert \int f d\mu -d\nu \vert$ for any $1$-Lipschitz function $f$. Take a triangulation ...
alesia's user avatar
  • 2,772
2 votes
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Are the sublevel sets of Boltzmann entropy compact in Wasserstein distance?

$\newcommand{\R}{\mathbb R}\newcommand{\H}{\mathcal H}$Building up on previous comments, and slighlty elaborating. The answer to your question, as is, is NO. Recall that convergence in the Wasserstein ...
leo monsaingeon's user avatar
2 votes
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Some continuity issues of the optimal transport map (Brenier map)

$\newcommand{\si}{\sigma}\newcommand{\W}{\mathcal W}\newcommand{\R}{\mathbb R} $Yes, the map \begin{equation*} \mu \mapsto J(\mu):=\int_\R T^\si_\mu(x+y)\exp(-y^2/2\si^2)\,dy \tag{10}\label{10} \...
Iosif Pinelis's user avatar
2 votes
Accepted

Connection between Wassertein-2 metric and difference in variance

Let $\mu_k$ and $\nu_k$ denote the $k$th moments of $\mu$ and $\nu$ respectively. Write $$W_p(\mu,\nu)=\inf\{\|X-Y\|_p\colon X\sim\mu,Y\sim\nu\},$$ where $\|Z\|_p:=(E|Z|^p)^{1/p}$. $\newcommand\si\...
Iosif Pinelis's user avatar
2 votes
Accepted

Unique coupling

The only way this can happen is the situation that you described, where at least one of the measures gives full measure to a single point. In fact, the proof below does not require the two Polish ...
Anthony Quas's user avatar
  • 23.2k
2 votes

Unique coupling

For two measurable sets $A,B$, let $p=\mu(A)$ and $q=\nu(B)$. Consider any coupling of a Bernoulli$(p)$ and a Bernoulli$(q)$, say, $C:\{0,1\}^2 \to [0,1]$. Then we can find a coupling $(X,Y)$ of $\mu$...
jlewk's user avatar
  • 1,724
1 vote
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Lipschitz approximation of a probability measure with finite $1$-st moment by the ones with finite $p$-th moment

$\newcommand{\R}{\mathbb R}$This is only a partial answer in the sense that it will provide $\frac 1p$-Hölder maps, not Lipschitz. I still hope it can help. Fix a big radius $R>0$ (I like $R\to\...
leo monsaingeon's user avatar
1 vote
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Gradient flows: evolution of geodesics

As currently asked the answer is NO, because your desired upper bound already fails for $t=0$ (or equivalently, $t=1$). Indeed, it is well understood that the small-time deviation along the heat flow, ...
leo monsaingeon's user avatar
1 vote

Are the sublevel sets of Boltzmann entropy compact in Wasserstein distance?

It is known that the sublevel sets of the relative entropy are tight when the reference measure is finite, and in fact are also compact in the topology of setwise convergence (which is stronger than ...
pseudocydonia's user avatar
1 vote

Lipschitz-type inequalities for Markov kernels

Assuming that your distance is convex, the question reduces just to the case when both $\mu$ and $\nu$ are delta measures, and amounts then to the inequality $$\tag {$\star$} d(\delta_x,\delta_y) \le ...
R W's user avatar
  • 17k
1 vote
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Is the Wasserstein distance to the empirical measure minimized by the underlying distribution?

No. E.g., let $N=1$ and suppose that $X:=X_1$ has a nondegenerate zero-mean distribution $\mu$ such that $E|X|^p<\infty$. Let $Y$ be an independent copy of $X$. Then the expected $\mathcal W_p$-...
Iosif Pinelis's user avatar

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