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9 votes
Accepted

Relationship between fans and root data

(1) A (connected) reductive group $G$ over an algebraically closed field $k$ is described by a combinatorial object called the based root datum ${\rm BRD}(G)$. (2) A spherical homogeneous space $Y=...
Mikhail Borovoi's user avatar
8 votes
Accepted

Is the complement of the open $B$-orbit in a spherical variety cut out by one equation?

The answer is yes, even if $X$ is not normal. It even works for any connected solvable group acting on an affine variety with an open orbit. To see this let $Y_1,\ldots,Y_r$ be the irreducible ...
Friedrich Knop's user avatar
7 votes
Accepted

Is there a Chevalley map for spherical varieties?

Edit: The answer to question 1 is yes if $G/H$ is a symmetric variety as the OP pointed out. For arbitrary spherical varieties the answer is no in general. If my memory serves me right, the spherical ...
Friedrich Knop's user avatar
7 votes

Spherical roots, restricted roots, and the dual group of a symmetric variety

There is a small survey published in an Oberwolfach report by Bart Van Steirteghem comparing the different normalizations of spherical roots in more detail. The standard normalization is obtained by ...
Friedrich Knop's user avatar
7 votes
Accepted

Uniqueness of the wonderful compactification of a semi-simple group

I assume you mean the variety $G$ considered as a $G \times G$ variety via the action $(g,h) \cdot x = gxh^{-1}$, which is the standard interpretation in the literature. The variety $G$ is spherical ...
Michael Joyce's user avatar
7 votes
Accepted

Spherical and Wonderful varieties

The only groups which act on only one wonderful variety are tori (with $X$ being a point). All other admit at least $X=G/B$ and $X=G/G$. If one fixes the open $G$-orbit then there is at most one ...
Friedrich Knop's user avatar
7 votes
Accepted

Number of boundary divisors and colors of a Spherical variety

There are relations coming from computing Picard groups in different ways. For simplicity let $G$ be semisimple. Let $x\in X$ be in the open $B$-orbit. Then $Bx=B/B_x$ and $Gx=G/G_x$ are open in $X$. ...
Friedrich Knop's user avatar
6 votes
Accepted

For a spherical pair $(G, H)$, which $G$-representations appear in $k[G/H]$?

Let $X_0=B/B_{x_0}=Bx_0$ be the open $B$-orbit in $X=G/H$. Then every character of $B$ which is trivial on $B_{x_0}$ yields a $B$-semiinvariant $f_\lambda$ on $X_0$. In general, it does not extend to ...
Friedrich Knop's user avatar
5 votes
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Spherical roots, restricted roots, and the dual group of a symmetric variety

You might already have found an answer, but hopefully this helps. The way I think about this is that there are always (at least) three normalizations of the roots to a spherical variety $X$. Some ...
Spencer Leslie's user avatar
5 votes
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Subvarieties of Lagrangian Grassmannians

Note first that, if $L$ is a Lagrangian contained in $H$ then $L^\perp = L$ contains $H^\perp$. So $X_n$ is non-empty only when $H$ is co-isotropic for your symplectic form. When $H$ is co-isotropic, ...
Nicolast's user avatar
  • 1,908
5 votes
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Gelfand pair, weakly symmetric pair, and spherical pair

I like this question! I originally thought it was much less subtle, and so posted some ill informed guesses in the comments. Although the notions of "weakly symmetric" and "Gelfand ...
LSpice's user avatar
  • 12.9k
4 votes

Relationship between fans and root data

Not an answer, but: you can construct a fan from a root system. Let $R$ be a root system in an Euclidean space, and let $\Lambda_R$ be the root lattice with dual lattice $\Lambda_R^\vee$. The fan $\...
skd's user avatar
  • 5,760
4 votes

Horospherical type of a spherical variety

As @LSpice pointed out, the group $S$ is not characterized by $N_G(S)=P^-$. Instead it is the normal subgroup of $P^-$ such that $P^-/S=T/T'$. Note also that $T'$ is in general not a subtorus of $T$ ...
Friedrich Knop's user avatar
4 votes

Representations with finitely many nilpotent orbits

This is a sequence of remarks and a partial answer the question. I won't accept it at this point in case someone can say something more general/ intelligent. Thanks to @Nandor for pointing out the ...
Spencer Leslie's user avatar
3 votes

Extending $p$-adic smooth and locally constant functions

Since $H^1(\mathbb Q_p, H)$ is finite and each fibre of $(G\cdot v)(\mathbb Q_p) \to H^1(\mathbb Q_p, H)$ is closed, we have that the fibre $G(\mathbb Q_p)\cdot v$ over the trivial cohomology class is ...
LSpice's user avatar
  • 12.9k
3 votes
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Connected components of a spherical subgroup from spherical data?

Let $H^\circ\subseteq H$ be the connected component of unity and let $M^\circ$ be weight lattice of $X^\circ:=G/H^\circ$. Since $\pi_0(H)=H/H^\circ$ acts as automorphisms on $X^\circ$ it follows that $...
Friedrich Knop's user avatar
3 votes
Accepted

Is any spherical subgroup conjugate to a subgroup defined over a smaller algebraically closed field?

The morphism $G/H\to\textrm{Spec}\,k$ is defined and flat over over some finitely generated $k_0$-subalgebra of $k$. Thus, the question amounts to whether a flat family of homomogeneous spherical $k_0$...
Friedrich Knop's user avatar
3 votes
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Action of $N(H)/H$ on the colors of a spherical homogeneous space $G/H$

The answer to both questions is "yes" as was communicated to me by Losev. The main reason is that already $\varsigma$ is almost injective. More precisely, the sets $\varsigma(D)$ are always non-empty ...
Friedrich Knop's user avatar
3 votes
Accepted

Morphisms of the spherical data of spherical homogeneous spaces

The situation is more complicated. First of all $\lambda_{\mathcal D}$ does not exist, since there may be colors in $X_1$ which map dominantly to $X_2$. The best way to describe morphisms $X_1\to X_2$ ...
Friedrich Knop's user avatar
3 votes

points with small U stabilizer on a spherical variety

This set is a special case of regular semisimple elements on spherical varieties. In particular it is open and dense.
Rami's user avatar
  • 2,639
2 votes

Finiteness of $H_1 \backslash G / H_2$ and the geometry of the orbits

This doesn't answer all your questions, but it seems relevant enough to post. In The orbits of affine symmetric spaces under the action of minimal parabolic subgroups by T. Matsuki(1977), the double ...
Sean Lawton's user avatar
  • 8,529
2 votes
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Bialynicki-Birula decompositions and fixed points

I think all of these should be easy enough to resolve. First note that (1) is a triviality from your assumption that $G$ has finitely many orbits on $X$, because a maximal torus of $G$ can only have ...
Sempliner's user avatar
  • 134
2 votes
Accepted

Element of Weyl chamber contracting $\mathbb{A}^n_k$ to a point

The answer to your question, as stated, is No. Take $G={\rm SL}_2$, $P=B$, $T'=T$. Note that you do not specify the isomorphism $T'\to {\Bbb G}_m^n$. Let us take the following isomorphism: $$T'\to {\...
Mikhail Borovoi's user avatar
2 votes
Accepted

An example of handle decomposition on modified $S^5$

I didn't really follow the details of your description, but here is a handle decomposition along the lines you suggest. Start with $((S^1 \times S^3)_a \coprod (S^1 \times S^3)_b) \times I$ where $I= [...
Danny Ruberman's user avatar
1 vote

Subvarieties of Lagrangian Grassmannians

Co-isotropic subspaces of dimension $n+k$ are in bijection with isotropic subspaces of dimension $n-k$. The variety of isotropic subspaces of dimension $n-k$ of a symplectic vector space of dimension $...
Puzzled's user avatar
  • 8,998

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