15
votes
Accepted
Has dynamics on $G/\Gamma$ ever been used to prove interesting things about $\Gamma$?
Where to begin!
The ergodicity of non-compact subgroups (singular tori) was used by Margulis to prove that higher rank lattices $\Gamma$ are arithmetic.
Once you have that $\Gamma $ is arithmetic, ...
Community wiki
14
votes
Accepted
Planes in Lagrangian Grassmannians
This is, indeed, true.
To prove this, assume we have an embedding $\mathbb{P}^2 \to \operatorname{LGr}(V)$ (where $V$ is a symplectic vector space). Let $U \subset V \otimes \mathcal{O}$ be the ...
14
votes
Accepted
Do all homogeneous spaces have homogeneous compactifications?
Since you want a connected example:
A surface of infinite genus has no homogeneous compactification.
Indeed first observe a dense locally compact subset has to be open.
So the surface has to be open, ...
13
votes
Accepted
Is a manifold paracompact? Should it be?
every group can be declared a Lie group if one allows the more general definition since one is permitted to have an uncountable number of connected components.
A manifold is paracompact if and only ...
13
votes
Examples of the Thurston geometries with transitive Lie group action
Here is a cool fact about $\mathrm{SL}(2, \mathbb{R}) / \mathrm{SL}(2, \mathbb{Z})$; it is homeomorphic to the complement of the trefoil knot in the three-sphere. Apparently this was first proved by ...
13
votes
Accepted
Classification of homogeneous Einstein manifolds
Yes, the question is still open.
I suggest to read this quite recent paper by Kerr and Böhm. It reviews some of the most important advances in the problem and includes several open problems.
12
votes
Accepted
Compact Lie group inclusions that are trivial on all homotopy groups
Well, the identity component $H^0$ of $H$ would have to be abelian, since, otherwise, it would have a compact simple component, and the induced map on $\pi_3$ would then be nontrivial.
If $H^0$ has ...
12
votes
Do all homogeneous spaces have homogeneous compactifications?
The countable discrete space $\omega$ is a counterexample.
Suppose $Y$ is a homogeneous compactification of $\omega$, with $X \subset Y$ being homeomorphic to $\omega$. As $Y$ is infinite, it ...
11
votes
Examples of the Thurston geometries with transitive Lie group action
These days, many popular quotients of ("real") hyperbolic three-space are obtained as $\Gamma\backslash SL_2(\mathbb C)/SU(2)$, where $\Gamma$ is the group of units in a quaternion division ...
11
votes
A manifold whose tangent space is a sum of line bundles and higher rank vector bundles
Remark: I assume that you want $A$ to be a non-trivial bundle. Otherwise, of course, any parallelizable compact manifold would be an example. In particular, any compact Lie group would be an ...
10
votes
Embeddings of flag manifolds
In general there is a more efficient way: $a_1,\ldots,a_k$ determines a Young diagram, and you can realize the flag variety as the stabilizer of a point in the unique closed orbit of ${\mathbb P}(U)$, ...
10
votes
How special are homogeneous spaces?
I suppose you want the action to be transitive as your title suggests. In this case, a classical theorem of Mostow (in 1950 for surfaces, in 2005 in general) says that for a compact homogeneous space $...
10
votes
Accepted
Non-homogeneous line bundles over a homogeneous space
Yes. This happens whenever $G$ admits nontrivial vector bundles $E$ which can be equipped with an equivariant structure for the $K$-action. Then $E$ descends in the same way to $G \times_{\rho} E \to ...
10
votes
Accepted
Non-integrable almost complex structure for complex projective $3$-space
There are lots of non-integrable almost-complex structures on $\mathbb{CP}^3$, but the one you are looking for is, I suspect, the following.
First I will explain the twistor fibration, which is a ...
10
votes
Accepted
A manifold whose tangent space is a sum of line bundles and higher rank vector bundles
You are asking about manifolds whose projective span is equal to $k$, according to the main definition of Grant and Schutte - Projective span of Wall manifolds.
Any manifold with zero Euler ...
9
votes
Accepted
Are invariant forms on homogeneous spaces necessarily closed?
Note that the answer depends on the pair $(G,K)$.
For example, if $K=\{e\}$, then one is asking whether the ring of left-invariant forms on $G$ consists only of closed forms. This only happens when $...
9
votes
Accepted
Homology of the free loop space of generalized flag varieties
Serre proved that for any simply-connected $X$, if $X$ has finitely generated homology groups in each degree, then the loop space of $X$ has finitely generated homology groups in each degree. (...
9
votes
Accepted
Examples of the Thurston geometries with transitive Lie group action
This is an answer to questions 7 and 8 (I have to say, having 8 questions in one post is way too much for my taste):
Suppose that $M$ is a finite-volume quotient of $H^3$ or a compact quotient of $H^...
8
votes
Has dynamics on $G/\Gamma$ ever been used to prove interesting things about $\Gamma$?
There's a nice proof by Margulis showing that arithmetic subgroups are indeed lattices using the famous Dani-Margulis non-divergence theorem.
Actually if you will investigate Ratner's original ...
Community wiki
8
votes
Flag manifolds as incidence correspondences
The "incidence" relation (at least for types $E_6$ and $E_7$) for all pairs of vertices $i$, $j$ is described in S. Garibaldi, M. Carr "Geometries, the principle of duality, and algebraic groups", ...
8
votes
Is a manifold paracompact? Should it be?
Another good gift of paracompactness:
A Hausdorff $C^k$ manifold ($k\ge0$) is metrizable iff it is
paracompact.
This is also true for infinite dimensional manifold modelled on a Banach space (...
8
votes
Separability of subspaces of homogeneous topological spaces
This fails even for topological groups. For example, the separable topological group $\mathbb{Z}^{\mathfrak{c}}$ contains a subgroup of uncountable cellularity (hence certainly not separable!). This ...
8
votes
Are the quaternionic Grassmannians quaternionic Kaehler manifolds?
Perhaps the OP really wants to know why quaternionic Grassmannians other than the quaternionic projective spaces are not considered to be 'quaternion-Kähler'.
The reason goes back to Berger's ...
8
votes
Accepted
Can all hermitian symmetric spaces be realised as coadjoint orbits?
This is true. One can use a few facts from Helgason's Differential Geometry, Lie Groups, and Symmetric Spaces to show that, indeed, $K = \mathrm{Stab}_G(Z)$.
Since $M=G/K$ is an irreducible Hermitian ...
8
votes
A manifold whose tangent space is a sum of line bundles and higher rank vector bundles
The product of a 2-sphere with a torus is an example. There are complex analytic examples due to Beauville (Complex manifolds with split tangent bundle). Every 3-manifold has trivial tangent bundle, ...
7
votes
Accepted
Ideal of the Spinor variety $S^{10}\subset\mathbb{P}^{15}$
Mukai, CURVES AND SYMMETRIC SPACES, I, (0.1)
7
votes
Accepted
Torus actions on $Sp(n)$-spheres
The presentation $\mathbb{S}^{2n-1} = \mathit{U}_n/\mathit{U}_{n-1}$ is tantamount to considering $\mathbb{S}^{2n-1}$ as the unit sphere in $\mathbb{C}^n$ (as $\mathit{U}_n$ is the group of $\mathbb{C}...
7
votes
Accepted
Automorphisms of homogeneous space $F_4/P_{\{\beta_2\}}$ over the exceptional group $F_4$
The following paper says that your map $\mu$ is indeed surjective; the author attributes the result over $\mathbb C$ to Tits.
...
7
votes
Accepted
k-flats in homogeneous spaces
If the k-flats are compact, then the space must be symmetric
(Molina-Olmos, J. Differential geometry
45 (1997) 575-592; see also Proc. Amer. Math. Soc. 129 (2001), 3701-3709).
Homogeneous spaces (non-...
7
votes
Accepted
The Quotients $SO(n)/SO(n-1)$, $O(n)/O(n-1)$ and $SO(n)/O(n−1)$
Yes, the branching is multiplicity free. See e.g. Theorem 8.1.3 and Theorem 8.1.4 in Symmetry, Representations, and Invariants by Nolan Wallach and Roe Goodman. The quotient space is a sphere $S^{n-1}$...
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