New answers tagged spectral-radius
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votes
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Tight upper bound on a ratio involving symmetric PSD matrices and Kronecker products
There is no upper for $m$ that is independent of $d$ and $T$. In fact, for a fixed $d$, the best upper bound that works for all $T$ is of order $\sqrt{d}$, and this is already tight for $T=d$.
The ...
3
votes
Accepted
Lower spectral radius of matrices with an invariant subspace
This is false; the result is not perfectly analogous because the definition of the spectral radius contains a maximum. Here is a counterexample.
Take
$$
A_1 = \begin{bmatrix}2 & 0\\ 0 & 1\end{...
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