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35 votes
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Consequences of eigenvector-eigenvalue formula found by studying neutrinos

The OP asks about generalisations and applications of the formula in arXiv:1908.03795. $\bullet$ Concerning generalisations: I have found an older paper, from 1993, where it seems that the same ...
Carlo Beenakker's user avatar
28 votes

Is the linear span of special orthogonal matrices equal to the whole space of $N\times N$ matrices?

For $n>2$, the span of the matrices in $\mathrm{SO}(n)$ is the full space $M_n(\mathbb{R})$ of $n$-by-$n$ matrices with real entries. One proof is using representation theory: If we let $S\subset ...
Robert Bryant's user avatar
22 votes

Expected value of determinant of simple infinite random matrix

Very nice problem! Let me recall you that the determinant of $n \times n$ matrices with entries in $\{0,1\}$ is related to the one of $n+1 \times n+1$ matrices with entries in $\{-1,+1\}$: replace ...
user39115's user avatar
  • 1,805
20 votes

Differentiability of Eigenvalues - Perturbation Theory

The complete reference is Kato's book Perturbation theory .... But perhaps you need only the most basic results. Then see my book Matrices (Springer GTM #216), 2nd edition. This is Section 5.2. Mind ...
Denis Serre's user avatar
  • 52.3k
19 votes

When the sum of positive definite matrices converges, does the sum of the norm of the associate matrices converges?

Yes. The norm of a positive definite matrix does not exceed its trace, and the sum of traces is finite, since the sum of diagonal elements is finite for each of $n$ places.
Fedor Petrov's user avatar
19 votes

Is the determinant the only multiplicative matrix function?

It depends on what is the target space. Linear representations of ${\bf Gl}_n(k)$ do satisfy $\rho(AB)=\rho(A)\rho(B)$ by definition, and they often extend in a natural way to ${\bf M}_n(k)$. On ...
Denis Serre's user avatar
  • 52.3k
18 votes

Is the linear span of special orthogonal matrices equal to the whole space of $N\times N$ matrices?

Let $S$ be the span of $SO(N)$ . Then it's obvious that if $A \in S$ and $D_1, D_2 \in SO(N)$ then $D_1^{-1} A D_2 \in S$ . Therefore it's enough to show that $B := diag(1,0,...0) \in S$ . If $N$ ...
jjcale's user avatar
  • 2,753
17 votes

Are unitarily equivalent permutation matrices permutation similar?

The answer is yes by an old theorem of Brauer. In fact, permutation matrices are conjugate over any field if and only if they are conjugate by permutation matrices. See this beautiful proof by ...
Benjamin Steinberg's user avatar
17 votes

Are unitarily equivalent permutation matrices permutation similar?

Here's a direct proof that if permutation matrices $A,B$ (of size $n\ge 0$) have the same characteristic polynomial (or equivalently are linearly equivalent, since these are diagonalizable) then they ...
YCor's user avatar
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17 votes
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Closed form solution for $XAX^{T}=B$

$B^{-1/2}XAX^TB^{-1/2}=I$, so $B^{-1/2}XA^{1/2}=Q$ must be orthogonal. On the other hand, for any orthogonal $Q$, it is simple to verify that $X = B^{1/2}QA^{-1/2}$ solves the equation, so this is a ...
Federico Poloni's user avatar
15 votes
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is it possible to have two non-isomorphic non-regular graphs with the same adjacent spectrum and the same laplacian spectrum?

Yes, Brendan McKay showed that almost all trees have mates that are simultaneously cospectral in both adjacency and Laplacian spectra. And more. http://users.cecs.anu.edu.au/~bdm/papers/SpectralTrees....
Gordon Royle's user avatar
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15 votes
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When does the determinant distribute over addition?

let me assume $A$ is invertible, then you ask when $$\det(1+X)=1+\det X,\;\;X=A^{-1}B $$ so if $X$ has eigenvalues $x_i$, $i=1,2,\ldots n$, you would need $$\prod_{i}(1+x_i)=1+\prod_i x_i$$ basically ...
Carlo Beenakker's user avatar
15 votes
Accepted

Is the linear span of special orthogonal matrices equal to the whole space of $N\times N$ matrices?

Elementary proof. The linear space $E$ spanned by $SO_n$ is the orthogonal of those matrices $M$ such that $\langle M,Q\rangle:={\rm Tr}(MQ)=0$ for every $Q\in SO_n$. Let $M=SR$ be a polar ...
Denis Serre's user avatar
  • 52.3k
14 votes
Accepted

Is every real matrix conjugate to a semi antisymmetric matrix?

Yes. Every matrix can be written as the sum of a symmetric plus an antisymmetric one: $A = \frac{A+A^T}{2}+\frac{A-A^T}{2}$. Now change basis such that the symmetric part is diagonal.
Federico Poloni's user avatar
14 votes
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Rank of $A\otimes B - B\otimes A$

For generic $A,B$ the matrix $A$ is invertible and $B=CA$, where $C$ is also generic. We have $(A\otimes B-B\otimes A)(u\otimes v)=Au\otimes CAv-CAu\otimes Av$. The vectors $Au$ run over the whole $\...
Fedor Petrov's user avatar
14 votes

Question on whether, "An entire function, nowhere zero, has an entire logarithm," holds for matrix-valued entire functions as well

Counterexample: Consider the entire function $$ A(z) = \pmatrix{e^z & 0\cr z & 1\cr}$$ An entire logarithm of $A(z)$ must have eigenvalues $z + 2\pi i n$ and $2 \pi ...
Robert Israel's user avatar
13 votes
Accepted

Differentiability of operator norm

It need not be differentiable everywhere. Let $P$ and $Q$ be mutually orthogonal self-adjoint projections. Then the norm of $P+ t Q$ is 1 for $|t| \leq 1$ and $|t|$ for $|t| > 1$. However, $\|A + ...
Nik Weaver's user avatar
  • 42.8k
13 votes

Consequences of eigenvector-eigenvalue formula found by studying neutrinos

I want to add to the list of places where this identity has been used previously. For a recent one, see arXiv:1710.02181 “State transfer in strongly regular graphs with an edge perturbation”. ...
Chris Godsil's user avatar
  • 12.1k
13 votes

One observation of special type of square matrix exponentiation

The answer is quite simple. First observe that $A$ is triangular, hence the spectrum is on the diagonal. From your assumptions, $1$ is a simple eigenvalue and the other eigenvalues belong to $[0,1)$. ...
Denis Serre's user avatar
  • 52.3k
12 votes
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Finding the nearest matrix with real eigenvalues

I have no idea what is going on, but your conjecture is not correct. This is more transparent perhaps in the complex version. Consider $$ A = \begin{pmatrix} i & a \\ 0&-i \end{pmatrix} , \...
Christian Remling's user avatar
12 votes

Matrix elements of exponential of tridiagonal matrices

Yes! Most methods to compute exponentials of large sparse matrices are based on computing directly $\exp(A)b$ for a given vector $b$ rather than the full matrix $\exp(A)$. Just take $b$ as a vector of ...
Federico Poloni's user avatar
11 votes
Accepted

When the sum of positive definite matrices converges, does the sum of the norm of the associate matrices converges?

You can bound $\|A_k\| \leq C(n)\max_{i,j} |(A_k)_{ij}|$ for some function of the dimension only $C(n)$, because all norms are equivalent in finite dimension. If I am not mistaken $C(n)=\sqrt{n}$, but ...
Federico Poloni's user avatar
11 votes
Accepted

Generalized Hölder's inequality for operator (subordinate) norms

Actually, there is a much stronger result, known as the Riesz-Thorin Theorem: The subordinate norm $\|A\|_p$ is a log-convex function of $\frac1p$. In other words, $$\left(\frac1r=\frac\theta{p}+\...
Denis Serre's user avatar
  • 52.3k
11 votes

Is the linear span of special orthogonal matrices equal to the whole space of $N\times N$ matrices?

Clearly the span of $SO(n)$ contains the tangent space of $SO(n)$, the antisymmetric matrices. But it also contains the rotations by $\pi$ in any 2-plane, so contains the diagonal matrices with even ...
Ben McKay's user avatar
  • 26.3k
11 votes
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How to see that the determinant of this matrix is nonzero for all primes?

As discussed in the comments, I don't see how to extract the desired matrix from the original question (about spanning the vector space). However, the matrix being nonzero IS equivalent to the ...
dhy's user avatar
  • 5,958
11 votes
Accepted

Is it true that $\lVert A\rVert \leq \lVert A^2\rVert$ for $A\in \operatorname{SL}(2, \mathbb{R})$ when $\operatorname{trace}(A)>2$?

We can do this by a calculation. The assumptions on the determinant and trace are equivalent to having eigenvalues $\lambda,1/\lambda$, with $\lambda>1$. We can rotate the first eigenvector to the $...
Christian Remling's user avatar
11 votes

Generating $\mathbf{PGL}_2(\mathbb{Z})$ and $\mathbf{PGL}_2(\mathbb{Q})$

For $PGL_2(\mathbb{Z})$, you can use general properties of arithmetic groups due to Borel and Harish-Chandra, which will carry over to rings of $S$-integers of number fields. Alternatively, you can ...
Aurel's user avatar
  • 5,382
10 votes
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Solving $\text{trace}\left[\left(I + pY\right)^{-1} \left(I - p^{2}Y\right)\right] = 0$ for scalar $p$

Write $Y=SDS^{-1}$, where $D$ is diagonal (since $X_1$ and $X_2$ are psd, $Y$ is diagonalizable). Then, observe that \begin{equation*} f(p) = \text{tr}(S^{-1}(I+pSDS^{-1})^{-1}SS^{-1}(I-p^2SDS^{-1})...
Suvrit's user avatar
  • 28.6k
10 votes

Expected value of determinant of simple infinite random matrix

I agree with user39115! I will give a heuristic from random matrix theory because we know the global behaviour of the eigenvalue. First $$A=p 1 +\sqrt{N(p-p^2)}\frac{B}{\sqrt{N}} $$ where $1$ is the ...
RaphaelB4's user avatar
  • 4,361

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