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38 votes
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Spectral symmetry of a certain structured matrix

For real $a,b,c$ and imaginary $d$ the matrix $A$ has chiral symmetry, meaning it anticommutes with a matrix $X$ that squares to the identity: $$X=\left( \begin{array}{cccc} 0 & 0 & 0 & -...
Carlo Beenakker's user avatar
27 votes

Is there a fast way to check if a matrix has any small eigenvalues?

Are you interested in a clever algorithm, or do you just want to get the answer fast? If the latter, then I would suggest the following: Use an established off-the-shelf eigenvalue solver. Vectorize ...
Nick Alger's user avatar
  • 1,160
23 votes
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Existence of double eigenvalue

The answer is 'no'. The generic pair $A$ and $B$ of $4$-by-$4$ Hermitian symmetric matrices will not have any nonzero real linear combination that has a double eigenvalue. For a specific example, ...
Robert Bryant's user avatar
23 votes

The statement that $A \ge B$ implies $A^{-1} \le B^{-1}$ is still true for matrices?

This is a well-known fact. A simple proof : setting $y=B^{1/2}x$, we have $\|y\|^2\le y^TB^{-1/2}AB^{-1/2}y$, that is $I_n\le B^{-1/2}AB^{-1/2}$. The eigenvalues of the latter symmetric matrix are ...
Denis Serre's user avatar
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20 votes

Differentiability of Eigenvalues - Perturbation Theory

The complete reference is Kato's book Perturbation theory .... But perhaps you need only the most basic results. Then see my book Matrices (Springer GTM #216), 2nd edition. This is Section 5.2. Mind ...
Denis Serre's user avatar
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20 votes
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Eigenvalue pattern

The explanation is pretty simple with a suitable change of basis. Letting $$B = \begin{pmatrix} 1 & 0 & 1 & 0 \\ i & 0 & -i & 0 \\ 0 & 1 & 0 & 1 \\ 0 & i &...
Antoine Labelle's user avatar
20 votes

Is there a fast way to check if a matrix has any small eigenvalues?

I am not sure if this is going to be faster than what you are doing now (which is already a clever method), but you can try the following. Compute $B = A^{-1}$. We know that $A$ has an eigenvalue in $...
Federico Poloni's user avatar
17 votes
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Showing that a certain matrix is not positive definite

Counterexample: let $k=7$, and let $B$ be the circulant matrix with $B_{ij}=1$ iff $i-j \in \{1,2,4\} \bmod 7$. Then $X_B$ is $I + \frac12 J$, with characteristic polynomial $(x-1)^6 (x-\frac92)$. ...
Noam D. Elkies's user avatar
17 votes
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Differentiability of eigenvalues of positive-definite symmetric matrices

In the open subset of $M_n(\mathbb{R})$ where the $\lambda_i$ are distinct, they are $C^{\infty}$ functions: this follows from the implicit function theorem. On the other hand, when some eigenvalue ...
abx's user avatar
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17 votes
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Counting eigenvalues without diagonalizing a matrix

Here is an efficient method. First of all, I must quote that diagonalizing $M$ is not a method, because there is no explicit way to carry this out. It amounts to calculating the roots of a polynomial !...
Denis Serre's user avatar
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16 votes
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What happens to eigenvalues when edges are removed?

The smallest eigenvalue can go up or down when an edge is removed. For "down": $G=K_n$ for $n\ge 3$. For "up": Take $K_n$ for $n\ge 1$ and append a new vertex attached to a single vertex of the ...
Brendan McKay's user avatar
16 votes

Differentiability of eigenvalues of positive-definite symmetric matrices

The keyword is the Cartan decomposition in the theory of symmetric spaces. In short, when an eigenvalue is simple (its multiplicity is $1$) it is locally an analytic function. But when the ...
Lior Silberman's user avatar
16 votes

Spectral symmetry of a certain structured matrix

An equivalent trick : Let $J:= \operatorname{diag}(1,i,-1,-i)$. Then $J^*AJ=iB$ where $B$ is real and skew-symmetric. Hence the spectrum of $iB$ (thus that of $A$) comes by pairs $\pm\lambda$.
Denis Serre's user avatar
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15 votes
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Eigenvalues of the complement of a graph

Edit (bis). There are two answers, depending on whether loops about vertices are allowed or not. In addition, the case of regular graphs is completely described. If loops are allowed The relation ...
Denis Serre's user avatar
  • 52.3k
15 votes
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Imaginary eigenvalues

Define the unitary and Hermitian matrices $$U=\left( \begin{array}{cccc} 0 & 0 & -i & 0 \\ 0 & 0 & 0 & -i \\ i & 0 & 0 & 0 \\ 0 & i & 0 & 0 \\ \end{...
Carlo Beenakker's user avatar
14 votes

Question on whether, "An entire function, nowhere zero, has an entire logarithm," holds for matrix-valued entire functions as well

Counterexample: Consider the entire function $$ A(z) = \pmatrix{e^z & 0\cr z & 1\cr}$$ An entire logarithm of $A(z)$ must have eigenvalues $z + 2\pi i n$ and $2 \pi ...
Robert Israel's user avatar
14 votes

Is there a fast way to check if a matrix has any small eigenvalues?

A symmetric matrix $A$ has an eigenvalue in $(-1,1)$ iff $A^2$ has an eigenvalue in $[0,1]$. Equivalently this means that $$ \min_{\Vert v\Vert=1} \frac{\Vert Av\Vert^2}{\Vert v\Vert^2} <1. $$ ...
Liviu Nicolaescu's user avatar
13 votes

Eigenvalue perturbation theory via Feynman diagrams

I think the simplest way is to use the very simple and very useful resolvant formula $$ (A+B)^{-1}=A^{-1}-A^{-1}B(A+B)^{-1}.$$ For perturbative theory, we just iterate this formula $$ (A+B)^{-1}=A^{-...
RaphaelB4's user avatar
  • 4,361
13 votes

Does there exist a nonsingular graph for which the determinant of its adjacency matrix remains the same upon deleting a vertex?

There exists a simple graph $G=(V,E)$ together with a vertex $v\in V$ such that $\operatorname{det}(A(G))$ and $\operatorname{det}\left(A(G\backslash\{v\})\right)$ are equal and non-zero. Example. ...
Philipp Lampe's user avatar
13 votes
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What is known about the eigenvectors of the $2^n \times 2^n$ Hadamard matrix?

The $2^n\times 2^n$ dimensional Hadamard matrices $H_{2^n}$ are also called Sylvester matrices or Walsh matrices. There are only two distinct eigenvalues $\pm 2^{n/2}$, so the eigenvectors are not in ...
Carlo Beenakker's user avatar
13 votes

Differentiability of eigenvalues of positive-definite symmetric matrices

As mentionned by other answers, simple eigenvalues are $C^\infty$, while non-simple ones are not. Let me add however two important properties which you can find in Kato's book Perturbation theory of ...
Denis Serre's user avatar
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13 votes
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Eigenvalues come in pairs

This follows from the identities $$A_1^{-1}=UA_1U^{-1},\;\;A_2^{-1}=UA_2U^{-1},$$ $$A_1^{\top}=VA_1V^{-1},\;\;A_2^{\top}=VA_2V^{-1},$$ with $$U=U^{-1}=\left( \begin{array}{cccc} 0 & 1 & 0 &...
Carlo Beenakker's user avatar
13 votes
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Is the eigenvalue map open?

Yes. Write $D(\lambda_1, \ldots, \lambda_n)$ as the diagonal matrix with diagonal entries $(\lambda_1, \ldots, \lambda_n)$. Let $A$ be any complex $n \times n$ matrix. We can upper-triangularize $A$ ...
David E Speyer's user avatar
12 votes
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Finding the nearest matrix with real eigenvalues

I have no idea what is going on, but your conjecture is not correct. This is more transparent perhaps in the complex version. Consider $$ A = \begin{pmatrix} i & a \\ 0&-i \end{pmatrix} , \...
Christian Remling's user avatar
12 votes

Are eigenvalues preserved under derived equivalence?

Let $A$ be the Nakayama algebra with Kupisch series [3,4], that is $A$ has quiver with two points 1 and 2 and an arrow $a$ from 1 to 2 and an arrow $b$ from 2 to 1 with relations $I=\langle aba\rangle$...
Mare's user avatar
  • 26.5k
12 votes
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Has Nambu's notion of an "eigenoperator" found a place in the mathematical literature?

Such an $X$ is an eigenvector of $\,\operatorname{ad}(H)$. Joint eigenspace decompositions of several $\operatorname{ad}(H_i)$ are commonplace in math since the work of Lie, Killing, Cartan, with the ...
Francois Ziegler's user avatar
11 votes

Eigenvalues and eigenvectors of the matrix with entries $\dbinom{n+1}{2j-i}$ for $i, j = 1, 2, \ldots, n$

Here is a proof for your identity in Question 3: define the functions \begin{equation} F(n,k):=\frac{\left(-1\right)^{k-i} \left(k-1\right)! \left(n-k\right)!} {2\left(i-1\right)! \left(n-i\right)!} \...
T. Amdeberhan's user avatar
11 votes

Differentiability of eigenvalues of positive-definite symmetric matrices

Let us consider functions $A$ from (an open interval in) $\mathbb{R}$ into the set of symmetric real $n\times n$ matrices (Hermitian complex $n\times n$ matrices behave analogously). If $A$ is given ...
Marc Nardmann's user avatar
11 votes
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Formula expressing symmetric polynomials of eigenvalues as sum of determinants

This is not a reference, but a short proof. We use the following (probably known, but see later) lemma on representing a symmetric tensor as a linear combination of rank-1 symmetric tensors. Lemma. ...
Fedor Petrov's user avatar
11 votes

Formula expressing symmetric polynomials of eigenvalues as sum of determinants

Concerning the reference request: Several text books [1,2] give the theorem and proof for elementary symmetric polynomials $s_k=$ sum of all $k\times k$ principal minors of the $n\times n$ matrix. ...
Carlo Beenakker's user avatar

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