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Prove that $ n \leq d+1 $ under ordering constraints in $\mathbb{R}^d$

For $d=2$ the maximal $n$ is $3=d+1$. Indeed, between 4 points $x_1,x_2,x_3,x_4$ either one of them, $x_k$, belongs to the convex hull of three others, then $\langle \theta,x_k\rangle$ can not be the ...
Fedor Petrov's user avatar
4 votes

Prove that $ n \leq d+1 $ under ordering constraints in $\mathbb{R}^d$

This is not a complete answer, but too large to fit reasonably as a comment. As shown by Fedor Petrov, it is not true that $n \leq d+1$, since for $d = 3$ we can construct $5$ such points and ...
user527492's user avatar

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