New answers tagged

1 vote

A combinatorial identity counting shellings of $K_n$

Yes, this is equivalent to the hypergeometric identity $${}_2F_1\biggl(\begin{matrix}a,-b\\c\end{matrix}\bigg|\;1\biggr) ={(a-c)(a-c-1)\dots(a-c-b+1)\over(-c)(-c-1)\dots(-c-b+1)};\quad\text{integer $b\...
ho boon suan's user avatar
5 votes
Accepted

Denominators of rational polytopes in terms of hyperplane coefficients

Let $x$ be a vertex of $\mathcal{P}$. By Cramer's rule, there is an $n \times n$ matrix $C$ such that each coordinate of $x$ is an integer multiple of $\frac{1}{|\det(C)|}$, and the absolute value of ...
Tony Huynh's user avatar
  • 30.2k
21 votes
Accepted

Does this expression always vanish?

Recall that $$ \sum_iA_i^{n-1}\prod_{j\neq i}\frac1{A_i-A_j}=1, $$ as follows from the Lagrange interpolation of $x^{n-1}$. Now apply $\prod_i \frac \partial{\partial A_i}$. We get $$ \sum_i\left((...
Ilya Bogdanov's user avatar
1 vote

Computing the expectation of a quadratic matrix form involving Bernoulli and Gaussian distributed matrices

$\newcommand{\ka}{\kappa}\newcommand{\si}{\sigma}$We have $\ka^2=ZHZ^TZHZ^T$ and hence, for $i$ and $j$ in $[n]:=\{1,\dots,n\}$, \begin{equation} (E\ka^2)_{ij}=\sum_{k,l,m,s,r}EZ_{ik}H_{kl}Z_{ml}...
Iosif Pinelis's user avatar
1 vote

Tree decomposition of graphs with low height

One way to address this question is to think of a tree decomposition as an unrooted tree. Then, it is easy to see that its diameter is related to the depth by a factor of 2. Searching for diameter, ...
Vinicius dos Santos's user avatar
0 votes

Computing the expectation of a quadratic matrix form involving Bernoulli and Gaussian distributed matrices

If $H$ has iid $N(0,1)$ entries, write $\kappa=\langle Z^TZ, H\rangle$ using the usual Frobenius inner product $\langle A,B\rangle = trace[A^TB]$. Conditionally on $Z$, $\kappa\sim N(0,\|Z^TZ\|_F^2)$ ...
jlewk's user avatar
  • 1,069
6 votes
Accepted

Sum of squares of chromatic roots of a bipartite graph

Consider the chromatic polynomial as a sum of monomials: $$P(G, k) = (k - r_1)(k - r_2)\cdots(k - r_n) = k^n + a_1k^{n-1} + \cdots + a_{n-1}k + a_n$$ It has been shown that $a_2 = \binom{e(G)}{2} - ...
1001's user avatar
  • 526
8 votes
Accepted

Conjecture about partitions of the powerset without the empty set

Here is a counterexample for $n=5$. Partition the non-empty subsets of $\{1, \dots, 5\}$ into the singleton subsets and a sixth family containing all the other non-empty subsets. So, $m=6$ and $|\...
Tony Huynh's user avatar
  • 30.2k
6 votes

Conjecture about partitions of the powerset without the empty set

Partition the subsets of $\{1,2,\dots, 100\}$ as $\{\mathcal{A_1},\ldots,\mathcal{A_6}\}$ by defining $$\mathcal{A_i}=\{S\in \mathcal{P}([100]) \setminus \{\emptyset\}: \text{all elements of S are} \,\...
Gjergji Zaimi's user avatar
3 votes

Conceptual reason why the sign of a permutation is well-defined?

Here is a formula I have not seen in the long and excellent list of answers: If $\sigma\in\mathfrak S_n$, then $\mathop{\rm sgn}(\sigma)=(-1)^{n-p}$, where $p$ is the number of orbits of $\sigma$ on $\...
ACL's user avatar
  • 12.6k
2 votes

Enumerating all inequivalent planar embeddings of a planar graph

I had this same problem. I couldn't find any actually implemented code after a lot of looking, but I did find some papers describing how to do it. The most promising was "A linear algorithm for ...
didericis's user avatar
1 vote

Clique number of $k$-critical graphs

For an upperbound, the clique number of a $k$-critical graph is obviously at most $k$, and this is achieved by the complete graph $K_k$. There is no non-trivial lowerbound for the clique number, and ...
Tony Huynh's user avatar
  • 30.2k
10 votes

Corners theorem in finite fields

Concerning your second question ...is there a known result of the form $r_\angle(\mathbb{F}_p^n)=O(c^{2n})$ for some $c<p$? This would, for the same reasons, imply that $r_3(\mathbb{F}_p^n)=O(c^n)$...
Eric Naslund's user avatar
  • 11.2k
5 votes

Combinatorial consequences of de Branges's Theorem?

In these lecture slides, Applications of de Branges–Rovnyak decomposition to graph theory Michio Seto reports on work with Sho Suda and Tetsuji Taniguchi on applications of de Branges–Rovnyak ...
Gerry Myerson's user avatar
7 votes

Ordinary partitions vs partitions into odd parts

For what it worth, here is a combinatorial proof. We start with a known Lemma 1. Let $m$ be an even positive integer. Then the number of permutations of $[m]$ with only odd cycles equals to the number ...
Fedor Petrov's user avatar
  • 96.8k
2 votes

Reference request for combinatorial problem related to $\max$ relation

I also don't have a reference, but I think one should be able to do this fairly explicitly as follows [it appears that Peter Taylor alludes to this strategy in their comment above]: First, note that ...
Christian Gorski's user avatar
9 votes

Ordinary partitions vs partitions into odd parts

Yes, they are the same. It is more convenient to write this in terms of compositions instead of partitions. Writing $\mathcal{OC}(n)$ for the set of compositions of $n$ with odd parts, the LHS is $$\...
lambda's user avatar
  • 1,432
10 votes
Accepted

Ordinary partitions vs partitions into odd parts

The g.f. for the right-hand is $$e^{2x}\cdot e^{2x^2} \cdots = e^{2\frac{x}{1-x}}.$$ For the left-hand side, additionally introducing variable $y$ to account for partition length, we get $$\sum_{n\...
Max Alekseyev's user avatar
4 votes

Enumerating all inequivalent planar embeddings of a planar graph

As suggested by Henrik Rüping in the comments, this problem can be solved in principle using the representation of embeddings by permutations, i.e., using combinatorial maps (aka "rotation ...
Noam Zeilberger's user avatar
1 vote

Topological characterisations of properties of posets

Recall that an Alexandrov space is a topological space where the intersection of arbitrary collection of open sets is open. Alexandrov duality states that the category of Alexandrov spaces is ...
Joseph Van Name's user avatar
1 vote

Perfect 1 error correcting codes non-isomorphic to Hamming codes?

You can find a lot of information in the recent book: "Perfect Codes and Related Structures," by T. Etzion. The notes to Chapter 5 contain a long list of references. In particular, if you're ...
Moshe Schwartz's user avatar
4 votes

Three-dimensional triangulations with fixed number of vertices

$\def\RR{\mathbb{R}}\def\ZZ{\mathbb{Z}}\def\Hull{\text{Hull}}$ This is a broken answer; it gives a triangulation of the lens space $L(3,1)$, not $S^3$. Step 1 The cylinder: Inside $\RR^3$, define $$\...
David E Speyer's user avatar
1 vote

On algebraic topology of coset complexes without geometry

Regarding your question (ii): So far as I know, proving the Nerve Lemma requires either a homotopy type argument, or a spectral sequence argument. You can find the spectral sequence argument in Ken ...
Russ Woodroofe's user avatar
0 votes
Accepted

Upper bounds estimates of Minkowski sum

No. As GH from MO said, there are plenty of sets $A,B\subset \Bbb{Z}$ where $|A+B|=|A||B|$, taking products of these such sets shows you can’t absorb these into the $O_d(\cdot)$. For example take $d\...
Zach Hunter's user avatar
  • 2,734
2 votes

On algebraic topology of coset complexes without geometry

This result is known to me as "Tits Lemma" (I learned it as part of the theory of buildings) and he proved it in Tits, Jacques, Ensembles ordonnés, immeubles et sommes amalgamées, Bull. Soc....
Max Horn's user avatar
  • 4,937
10 votes
Accepted

Submodule lattices of preprojective algebras

Here is an answer to question (2), strongly inspired by Dave Benson's comment: Theorem Let $A$ be any ring and let $M$ be a finite length $A$-module. Then the lattice of $A$-submodules is distributive ...
David E Speyer's user avatar
1 vote

On the number of intersection points between a curve and a (horizontal, vertical) line inside a unit square

The following claim and its proof answer OP's question, but only under an additional hypothesis on the critical points of the coordinate functions $\gamma_i$ of the curve $\gamma = (\gamma_1, \dots, \...
Luc Guyot's user avatar
  • 7,138
1 vote
Accepted

Find an order-embedding of $S_3\times{\bf2}\times{\bf2}$ into ${\mathbb Z}^4$

We present an embedding into $\mathbb Z^3$. It is symmetric with respect to the premutation of the coordinates in $S_3$, so it suffices to show the images of the following elements $((x,y,z),a,b)\in ...
Ilya Bogdanov's user avatar
2 votes

Topological characterisations of properties of posets

I will discuss Question 1: Is there a nice purely topological characterisation when a connected finite topological space with $T_0$ corresponds to a lattice and when this lattice is distributive? ...
Keith Kearnes's user avatar
0 votes

Sequences that don't count algebraic structures on finite sets

Because it's too long for a comment I'll post this as an answer: I just want to provide Omar Antolín's nice proofs of the following facts. These facts probably go back to this paper: László Lovász, ...
John Baez's user avatar
  • 20.9k
3 votes

Is matroid realizability computable?

A matroid being representable is equivalent to a certain locally closed subscheme of the Grassmannian, defined by the non-vanishing of the Plücker coordinates corresponding to bases and the vanishing ...
Matt Larson's user avatar
5 votes

Is "do-almost-nothing" ever winning on large CHOMP boards?

Using this code, I've searched up to $15×15$ and $6×65$. Improved memory management is required to go further. The only large (not $2×n$) boards on which the minimal move is winning in this range ...
Sam Benner's user avatar
9 votes

Sequences that don't count algebraic structures on finite sets

The original question was: My question is: can anyone name a sequence $(a_n)_{n\geq 1}$ of natural numbers that grows more slowly than exponentially, yet is not a model sequence? Any model sequence $(...
Keith Kearnes's user avatar
6 votes
Accepted

Does Kalai's $3^d$ conjecture hold for simplicial spheres?

The reference for Kalai's conjecture for simplicial polytopes is Richard Stanley's paper On the number of faces of centrally-symmetric simplicial polytopes which includes the theorem: Let $A$ be a $(...
Will Sawin's user avatar
  • 129k
0 votes

Sign-reversing involution for $q$-binomial coefficient at $q=-1$

I am recording here the algebraic proof using exterior powers of vector spaces. I think it makes for an interesting comparison to Will Sawin's very nice answer, because here the reverse really appears....
7 votes
Accepted

Sign-reversing involution for $q$-binomial coefficient at $q=-1$

Here is a uniform proof: Consider the involution on words $w_1,\dots,w_n$ of length $n$ that takes the first $j$ such that $1 \leq j \leq n/2$ with $w_{2j-1}$ and $w_{2j}$ distinct and swaps $w_{2j-1}$...
Will Sawin's user avatar
  • 129k
4 votes

On the number of intersection points between a curve and a (horizontal, vertical) line inside a unit square

Let $\varphi: [0,L] \to [0,2\pi)$ give the direction of the curve. Then the number of intersected horizontal lines (with multiplicities) is given by $\int_0^L |\sin\varphi(t)| dt$. Similarly, the ...
domotorp's user avatar
  • 18.4k
0 votes

Khovanskii's theorem on iterated sumsets

Your idea is essentially correct. Suppose $x\in\mathbb N_0^r$ is useless. Then either there does not exist any useless $x_1\in\mathbb N_0^r$ satisfying $x_1\le x$, in which case $x\in X$ and trivially ...
ho boon suan's user avatar
2 votes

Graph alignment by considering node and edge weights

This is a very interesting problem, although I'm not sure if it's a mathematical problem exactly (as opposed to one of algorithmic modeling). That said, here are some two suggestions. Suggestion #1: ...
Bill Bradley's user avatar
  • 3,700
4 votes
Accepted

Some necessary condition for $\gcd(m,n) $ be a proper divisor of $\gcd(mk_2 +nk_1,mn) $

Yes, Statement 1 does imply Statement 2. With $$d = \gcd(m, n), \;\; m = de, \;\; n = df, \;\; \gcd(e, f) = 1 \tag{1}\label{eq1A}$$ then $$\gcd(mk_2 + nk_1, mn) = \gcd(dek_2 + dfk_1, d^2ef) = d\gcd(...
John Omielan's user avatar
2 votes
Accepted

Isomorphism of two regular hypergraphs

No. There are already multiple isomorphism classes of regular graphs. Consider two disjoint triangles (i.e., $\{12,23,31\}\cup \{45,56,64\}$), versus a cycle of length 6 ($\{12,23,34,45,56,61\}$).
Zach Hunter's user avatar
  • 2,734
4 votes
Accepted

Determining graph Isomorphism: combining invariants

There will be strongly-regular graphs of the same parameters with equal values of all those invariants. Since the parameters determine the eigenvalues, all the invariants determined by the spectrum (...
Brendan McKay's user avatar
3 votes

Reference for group-algebra/exp-log like identites in combinatorics

A good starting point for a literature search on this and related types of inversion formulas is OEIS A036040 which will lead you to a slew of general theorems and generalizations as well as explicit ...
Tom Copeland's user avatar
  • 9,377
0 votes

What is a chess piece mathematically?

Rereading the questions, I would simply answer that with the basic rule of chess one can consider the pieces as instances (or initializations on a game board) take from mobility classes that directly ...
dbdb's user avatar
  • 1
12 votes

Reference for group-algebra/exp-log like identites in combinatorics

The reason this is called the "exp-log" correspondence is that it can be written in terms of formal power series as follows: write $G(z) = \sum g_n z^n, F(z) = \sum f_n z^n$. We need the ...
Qiaochu Yuan's user avatar
3 votes
Accepted

A second attempt at a two-dimensional Higman's Lemma

The answer is still no. Here is a counterexample for three letters $X,Y,Z$; With a bit of care in the arguments, it can be fir into two letters. For convenience, we present a sequence where indices ...
Ilya Bogdanov's user avatar
7 votes
Accepted

Elegant proof for $xy < yx \Leftrightarrow x^\mathbb{N} < y^\mathbb{N}$

Let $x, y \in \Sigma^+$. Observe that for all $n \in \mathbb{N}$ the inequality $xy<yx$ implies that $$x^ny^n<y^nx^n$$ by repeatedly swapping pairs of $x$ and $y$. It follows that $x^\mathbb{N}\...
6 votes
Accepted

Congruences for power-sum of divisors

I wrote an answer in the comment section, so I'll rewrite it here. The claim of $$F_1(q)-F_3(q)\equiv F_1(q^p) \pmod p$$ is equivalent to the following two cases $$p\nmid n: \sum_{d|n} d-nd^3 \equiv ...
user196574's user avatar
9 votes
Accepted

Estimate of Minkowski sum

This is only a partial answer to your question; I believe there is more current work, and have forwarded your question to someone working in this area to see if they have more recent results. In ...
Terry Tao's user avatar
  • 104k
5 votes
Accepted

Arboricity and average degree

Denote $A(G)=A$. Let $H$ be the subgraph for which $\lceil \frac{|E_H|}{|V_H|-1}\rceil=A$. Write $e$ for $|E_H|$, $v$ for $|V_H|$. We have $e/(v-1)>A-1$, thus $e>(v-1)(A-1)$. On the other hand, $...
Fedor Petrov's user avatar
  • 96.8k

Top 50 recent answers are included