9 votes
Accepted

In what sense exactly are the Einstein metrics distinguished?

If I understood your question correctly, the answer indeed is due to Lovelock. I think it's important to state all the hypotheses clearly, because they are not always reported accurately. Theorem. (...
Igor Khavkine's user avatar
8 votes
Accepted

Does exist a Kahler-Einstein metric on the blow-up of $\mathbb{P}^3$ along a smooth plane cubic?

No, there are no Kähler—Einstein metrics on the blow-up of $\mathbb{P}^3$ along a plane cubic. Let $X$ be the blow-up of $\mathbb{P}^3$ along a plane cubic. Then the alpha-invariant $\alpha(X)=1/4$ ...
Chen Jiang's user avatar
  • 1,084
7 votes

Does there exists a complete Kahler metric with positive scalar curvature on Poincare disk?

Take any smooth function $f$ on the disk so that $f$ goes to infinity at the boundary and then our metric must be of the form $g=e^f(dx^2+dy^2)$. Every metric on any oriented surface is Kaehler, in ...
Ben McKay's user avatar
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5 votes
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Kähler-Einstein metrics on singular varieties

Yes, this is a result of Essydieux-Guedj-Zeriahi: "Singular Kähler-Einstein metrics" J. Amer. Math. Soc. 22 (2009), 607-639.
Ruadhaí Dervan's user avatar
5 votes
Accepted

Is there any relativistic interpretation on considering Kaehler-Einstein metrics and Calabi-Yau manifolds?

First, a purely mathematical remark: it is not so easy to construct Riemannian Ricci-flat metrics on compact manifolds. Ricci flat Kähler (= Calabi-Yau) metrics give a large class of examples and are "...
user25309's user avatar
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4 votes

Does there exists a complete Kahler metric with positive scalar curvature on Poincare disk?

The answer to your question is no.In case of surfaces the scalar curvature and Ricci curvature coincide with Gauss curvature. If an n dimensional M had a complete Riemannian metric h with nonnegative ...
Mohan Ramachandran's user avatar
4 votes

Uniqueness of a compatible Kahler-Einstein structure on a symplectic manifold?

Let $X$ be a smooth complex del Pezzo surface which forms non-trivial family (for example the cubic surface). Then by a Theorem of Tian every variety in the family will have a KE-metric ( Tian, G. On ...
Nick L's user avatar
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4 votes

Examples of constant scalar curvature kähler metric that is not kahler einstiein

Here is a non-compact example. Consider the half-space $ \mathbb{C} \times \mathbb{H}$ as a subset of $ \mathbb{C}^2$. We use the Kahler potential $$\Psi = \frac{x_1^2}{x_2} - \log(x_2).$$ Here, $...
Gabe K's user avatar
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3 votes

In what sense exactly are the Einstein metrics distinguished?

OK I think I understand the question now. You want to look at Lovelock gravities. These are the most general theories (not bothering with a list of qualifiers here, see wikipedia) that produce 2nd ...
AlexArvanitakis's user avatar
3 votes
Accepted

Uniqueness of a compatible Kahler-Einstein structure on a symplectic manifold?

Concerning 2) one can, of course, take the product of two curves of higher genus to get a counter-example. In general, to have a statement as you want, one should look for rigid complex surfaces of ...
Dmitri Panov's user avatar
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2 votes
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$\partial \overline{\partial}$-lemma for Irreducible, Normal Projective Varieties

This just follows from the definition of admissible. Indeed $\omega_1 = c(\omega_{FS} + i\partial\bar\partial \psi_1),$ and $\omega_2 = c(\omega_{FS} + i\partial\bar\partial \psi_2$). Thus $\omega_1 ...
Ruadhaí Dervan's user avatar
2 votes

CSC Kahler metrics on a blown-up torus

This statement about blow ups of torus is not correct. Take any aglebraic $2$-torus with a smooth curve $C$ of genus $>1$. Blow up $C^2+1$ points on $C$ and apply Theorem 1 here: https://arxiv.org/...
aglearner's user avatar
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2 votes
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Surface with Kahler-Einstein metric

There answer is no. The topological manifolds $\mathbb{CP}^2 \sharp k \overline{\mathbb{CP}^2}$ admit smooth structures that support KE with negative scalar curvature for k=5, 6, 7, 8 For k=8, see ...
Martin de Borbon's user avatar
1 vote

Request for non-Einstein positive constant scalar curvature Kähler surfaces

I unfortunately am not able to comment, so I’ll have to write what I can say here: As you point out, the compact surfaces admitting Kähler metrics of positive Ricci curvature, i.e., Del Pezzo surfaces,...
KyleBroder's user avatar
1 vote

Examples of constant scalar curvature kähler metric that is not kahler einstiein

$\newcommand{\Proj}{\mathbf{P}}$Examples of compact constant scalar curvature Kähler manifolds that are not Einstein are constructed by solving explicit ODEs in On existence of Kähler metrics with ...
Andrew D. Hwang's user avatar
1 vote
Accepted

First Chern class with sign

See Demailly, Complex Algebraic and Differential Geometry, p.333. By definition, the first Chern class of a vector bundle is positive (negative, zero) if it is positive (negative, zero) as a ...
Ben McKay's user avatar
  • 25.6k
1 vote
Accepted

Kähler metric of constant scalar curvature with positive bisectional curvature is Kähler-Einstein

I assume your manifold is compact. It follows from Siu-Yau's proof of the Frankel conjecture that your manifold $X$ is biholomorphic to projective space (see also Mori's work) [1]. In particular, $\...
Ruadhaí Dervan's user avatar

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