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8 votes

algebraic de Rham cohomology of singular varieties

A very explicit example is given by the cusp $X=\operatorname {Spec}(A)$ where $A=\frac {\mathbb C[\xi,\eta]}{(3\eta^2-2\xi^3)}=\mathbb C[x,y]$. Since the set of closed points $X(\mathbb C)$ in its ...
Georges Elencwajg's user avatar
4 votes
Accepted

Degeneration of Hodge-de Rham spectral sequence, exactness of a pairing and the trace morphism

First of all, Deligne-Illusie worked with relative Frobenius $F = F_{X/S}: X \to X'$, so the target of the composition should be $\Omega_{X'/S}^p$ instead of $\Omega_{X/S}^p$. Your question about why ...
HYL's user avatar
  • 1,829
4 votes

When is the module of Kahler differentials free?

This is just expanding my comment above (which I messed up forgetting dollar signs). For simplicity, let me assume that $X\subset\mathbb{A}^n$ be a $d$ dimensional smooth variety with $\Omega^1_X$ ...
Mohan's user avatar
  • 6,262
4 votes
Accepted

Residue of the canonical sheaf along subvariety

I believe that what you wrote is not entirely correct and that might be the reason that it does not seem to work out. As a response to one of your comments, $K_C$ actually makes sense in this case, ...
Sándor Kovács's user avatar
3 votes
Accepted

Is there an analogue of the module of differentials for "higher order derivations" in the Hochschild/cyclic senses?

The answer is yes and it is very simple. It helps to understand the case $n=1$ first in the way I explained in my thesis in Prop. 4.5.3. Namely, $\Omega^1_{S/R}$ can be constructed as the quotient of ...
Martin Brandenburg's user avatar
2 votes
Accepted

Kähler differentials on an Artinian local ring

I finally remembered the example (though not the reference). Take $f=x^2y^2+x^5+y^5\in R=\mathbb{C}[[x,y]]$. Then $f_x,f_y$ form a regular sequence in $R$ and thus $R/I$ where $I=(f_x,f_y)$ is an ...
Mohan's user avatar
  • 6,262
2 votes
Accepted

Categorical Kähler differentials and the Leibniz rule

1. The Leibniz rule follows immediately from the last description of derivations as morphisms of commutative rings X:R→u(M). Indeed, u(M) is the square-zero extension of some R-module M' (in the ...
Dmitri Pavlov's user avatar
1 vote

Confusion about the (Grothendieck–Poincaré) double dual of reflexive differentials vs usual differentials on a normal Cohen–Macaulay scheme

I believe you are confusing local duality (on a Cohen–Macaulay loal ring) and global duality on a scheme. On a scheme $X$ with dualizing complex $\mathcal{K}^{\bullet}$, Serre–Grothendieck duality is ...
Libli's user avatar
  • 7,300
1 vote

The left exactness of conormal sequence when $X$ is singular

It is easier to think in terms of smoothness instead of nonsingularity (by Grothendieck's EGA 0$_{IV}$ 22.5.8, both comcepts are the same if the base field $k$ is perfect). Then EGA 0$_{IV}$ 22.6.1, ...
A.G's user avatar
  • 533

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