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first-order and higher-order logic, model theory, set theory, proof theory, computability theory, formal languages, definability, interplay of syntax and semantics, constructive logic, intuitionism, philosophical logic, modal logic, completeness, Gödel incompleteness, decidability, undecidability, theories of truth, truth revision, consistency.

60 votes
7 answers
9k views

In what respect are univalent foundations "better" than set theory?

It was an ambitious project of Vladimir Voevodsky's to provide new foundations for mathematics with univalent foundations (UF) to eventually replace set theory (ST). Part of what makes ST so appealing …
5 votes
1 answer
150 views

Intersection cardinalities in MAD families

Let $\newcommand{\o}{[\omega]^\omega}\o$ denote the collection of infinite subsets of the set of nonnegative integers $\omega$. We say ${\cal A}\subseteq \o$ is almost disjoint if $A\cap B$ is finite …
4 votes
1 answer
151 views

Minimal dominating sets in thin hypergraphs

Let $H=(V,E)$ be a hypergraph. We say that $H$ is thin if for every $v\in V$ the set $E_v=\{e\in E:v\in e\}$ is finite. A subset $D\subseteq V$ is dominating if $\bigcup \{e\in E:e\cap D \neq \emptyse …
20 votes
1 answer
534 views

Almost orthogonal maps $f:\omega \to \{-1,1\}$

Let $\omega$ denote the set of non-negative integers. For sets $A,B$, let $B^A$ denote the set of maps $f:A\to B$. For $f,g\in\{-1,1\}^\omega$ we say that $f,g$ are almost orthogonal if there is $C_0\ …
3 votes
1 answer
196 views

Mutually equal Hamming distance of members of ${\cal P}(\mathbb{N})$

This is inspired by an older, as of yet unanswered question. If $X$ is a set and $A,B\subseteq X$, we let the Hamming distance of $A, B$ be defined as $d_H:=\text{card}\big((A\setminus B)\cup (B\setmi …
5 votes
1 answer
166 views

Cardinality of separating families on an infinite cardinal $\kappa$

Let $\kappa$ be an infinite cardinal. We say ${\cal S}\subseteq {\cal P}(\kappa)$ is separating if whenever $a\neq b\in \kappa$ there is $T\in {\cal S}$ such that $|T\cap\{a,b\}| = 1$. Let $\newcomman …
5 votes
1 answer
212 views

Image-catching families in $\omega$

Let $[\omega]^\omega$ be the collection of infinite subsets of the set of nonnegative integers $\omega$, and let $\newcommand{\I}{\cal{I}}\I=$ $\{S\in[\omega]^\omega: (\omega\setminus S)\in[\omega]^\o …
7 votes
1 answer
450 views

Is it consistent that $|[\kappa]^{<\kappa}| > \kappa$?

Let $\kappa>\aleph_0$ be a cardinal, and let $[\kappa]^{<\kappa}$ denote the collection of subsets of $\kappa$ having cardinality strictly less than $\kappa$. Is it consistent that $$|[\kappa]^{<\kapp …
2 votes
1 answer
167 views

Smallest ${\mathbf B}$-function $f:\omega\to( \omega\setminus\{0\})$

Motivation. Every hypergraph $(\omega, E)$ where $E$ is countable and consists of infinite sets has property $\newcommand{\B}{\mathbf{B}}\B$. On the other hand, if the members of $E$ are allowed to be …
3 votes
1 answer
143 views

Large almost disjoint family on $\mathbb{N}$ with property $\mathbf{B}$

Let $\newcommand{\oo}{[\omega]^\omega}\oo$ denote the collection of all infinite subsets of the set of nonnegative integers $\omega$. We say that $\newcommand{\ss}{{\cal S}}\S\subseteq \oo$ haspropert …
23 votes
2 answers
3k views

Does the "three-set-lemma" imply the Axiom of Choice?

Consider the following curious statement: $(S)$ $\;$ Let $X$ be a non-empty set and let $f:X \to X$ be fixpoint-free (that is $f(x) \neq x$ for all $x\in X$). Then there are subsets $X_1, X_2, X_3 …
2 votes
1 answer
171 views

Chromatic number and taking duals of hypergraphs

If $H=(V,E)$ is a hypergraph and $\kappa\neq \emptyset$ is a cardinal, then a map $c:V\to \kappa$ is said to be a colouring if for every edge $e\in E$ with $|e|\geq 2$ the restriction $c\restriction_e …
2 votes
0 answers
46 views

Chromatic number of the dual hypergraph [duplicate]

Let $H = (V,E)$ be a hypergraph. For $v\in V$ we set $E_v = \{e\in E: v\in E\}$. The dual of $H$ is defined by $H^* =(E, V^*)$ is, where $V^* = \{E_v:v\in V\}$. If $\kappa>0$ is a cardinal, a map $c:V …
10 votes
2 answers
234 views

Additive, multiplicative, and Dedekind infiniteness in ${\sf (ZF)}$

We call a set $X$ Dedekind-infinite if there is an injective map $f:X\to X$ that is not surjective, addititvely infinite if $X \neq\emptyset$ and there is an injective map $f:\big((X\times\{1\})\cup( …
5 votes
1 answer
166 views

The equivalence of Dedekind-infinite and dually Dedekind-infinite as a weak form of (AC)

A set $X$ is Dedekind-infinite if there is an injective map $f: X\to X$ that is not surjective. A set $X$ is dually Dedekind-infinite if there is a surjective map $f: X\to X$ that is not injective. In …

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