Search Results
Search type | Search syntax |
---|---|
Tags | [tag] |
Exact | "words here" |
Author |
user:1234 user:me (yours) |
Score |
score:3 (3+) score:0 (none) |
Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
Views | views:250 |
Code | code:"if (foo != bar)" |
Sections |
title:apples body:"apples oranges" |
URL | url:"*.example.com" |
Saves | in:saves |
Status |
closed:yes duplicate:no migrated:no wiki:no |
Types |
is:question is:answer |
Exclude |
-[tag] -apples |
For more details on advanced search visit our help page |
Banach spaces, function spaces, real functions, integral transforms, theory of distributions, measure theory.
11
votes
1
answer
746
views
Generalized limits on $\ell^\infty(\mathbb{N})$
Let $\ell^\infty(\mathbb{N})$ denote the set of bounded real sequences $(a_n)_{n\in\mathbb{N}}$. The $\lim$ operator is a partial linear operator from $\ell^\infty(\mathbb{N})$ to $\mathbb{R}$. With t …
5
votes
Is every continuous function measurable?
If $X, Y$ are topological spaces such that for every continuous map $f: X\to Y$ and any $K\subseteq Y$ compact, $f^{-1}(K)$ is a compact of subset of $X$, then every continuous function is measurable. …
1
vote
A question about Skorokhod metric
In the answer to the following comment, it is shown why $\rho(x,x') = 0$ implies $x = x'$: https://math.stackexchange.com/questions/163678/a-proof-that-skorohod-metric-is-a-metric
1
vote
Skorokhod distance between $\omega, \omega\circ f_{\varepsilon}$ and $\omega, \omega\circ b_...
The answer to the question is No. Let $x:[0,1] \to [0,1]$ be defined by $x(t) = 0$ for $t\in [0,1/2[$ and $x(t) = 1$ for $t\in[1/2, 1]$. Clearly, $x$ is cadlag and therefore a member of $D([0,1], R)$. …
1
vote
Relation between two different definitions for relative sequential compactness
One important class of spaces for which the two definitions mentioned in the post are equivalent, are the first-countable spaces. One of the most important properties of any first-countable space $(X, …