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3
votes
0
answers
247
views
Universal cover of finetely connected surface with boundary
Let $M$ be a finetely connected orientable surface with compact boundary. This means $M$ is homeomorphic to a compact orientable surface $\Sigma$ of genus $g \geq 0$ minus $r \geq 1$ points and minus …
-2
votes
1
answer
506
views
Local isometry implies covering map: nonempty boundary case [closed]
The following theorem is well known in the literature:
Let $M$ and $N$ be riemannian manifolds and let $f : M \to N$ be a local isometry. If $M$ is complete and $N$ is connected, then $f$ is a cov …
1
vote
0
answers
56
views
Existence of holomorphic coverings having small degree
Let $\Sigma$ be a closed Riemann surface of genus $g$. In the book of Farkas and Kra, they prove that there exists a holomorphic covering map $F : \Sigma \to \mathbb{S}^2$ of degree less than or equal …