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A Banach space is a complete normed vector space: A vector space equipped with a norm such that every Cauchy sequence converges.

1 vote
1 answer
229 views

An approximation property in a separable topological vector space

Let $X$ be a topological vector space. Let us say that $X$ enjoys sequential separablity if there exists a sequence $\{x_n\}$ in $X$ such that for every $x\in X$ there exists a subsequence of $\{x_ …
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  • 4,058
2 votes
1 answer
165 views

A formula for vector valued measurable functions

Let $B_{\infty}(\Omega)$ be the space of bounded measurable functions on the measurable space $\Omega$. For a given Banach space $X$, let us denote $B_{\infty}(\Omega,X)$ by the set of all bounded m …
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  • 4,058
7 votes
1 answer
285 views

Does separability of the strong operator topology imply separability of the underlying space?

Let $X$ be a Banach space and $B(X)$ be the space of bounded operators on $X$. Suppose that the strong operator topology on $B(X)$ is separable and that the cardinal number of $B(X)$ is continuum. …
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8 votes
2 answers
484 views

If the cardinality of $B(X)$, the space of operators on $X$, is continuum, must $X$ be separ...

Does there exits any non-separable Banach space $X$ such that the size (cardinal number) of $B(X)$, bdd linear operators on $X$, is just of the continuum?
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2 votes
1 answer
228 views

Relation between the weak star topology and hereditary Lindelöfness

Let $X$ be a Banach space. Is the following implication valid? $$ (X,w) \textrm{ is hereditarily Lindelöf}~ \Rightarrow X^*~ \textrm{is separable} $$ The converse is clearly true, since the close …
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  • 4,058
4 votes
2 answers
329 views

pointwise convergence to the identity

Let $X$ be a separable topological vector space with size (cardinal number) no larger than $\mathfrak{c}$. Does there exist any sequence of finite rank linear maps $\phi_n:X\to X$ pointwise converging …
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  • 4,058
4 votes
0 answers
115 views

point-wise approximation of the identity in hereditary Lindelof spaces

Let $X$ be a topological vector space. Assume that there exists a sequence of finite range measurable functions $\phi_n:X\to X$ with $\lim\phi_n(x)=x$. Q. Can we concluded that $X$ is hereditery Li …
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2 votes
3 answers
3k views

$c_0$ is not isometrically isomorphic to $c$

Let us consider the space of convergent sequences which is denoted by $c$. The space of all sequences $(x_n)\in c$ with $\lim x_n=0$ is also denoted by $c_0$. Clearly $c_0$ is a proper closed subspac …
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2 votes
1 answer
151 views

A particular separation example

Q1. Does there exist a separable Banach space $X$ satisfying in the following property? 1- $X^*$ is non separable. 2- For every countable subset $F\subset X^*$ there exists $0\neq x_F\in X$ suc …
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5 votes
1 answer
194 views

The largest topological copy of a Hilbert space contained in $\ell^1$

Let us consider $\ell^1$, the space of absolutely summable sequences in the space of complex numbers. Clearly every finite dimensional Hilbert space is topologically embedded into $\ell^1$. Conven …
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9 votes
1 answer
377 views

Comparing two $\sigma$-algebras on $B(\ell^1)$

Let us consider $B(\ell^1)$, bounded linear operators on $\ell^1$. We recall the weak operator topology, denoted by $w$, on $B(\ell^1)$ is determined as follow $$w-\lim T_i=T \Longleftrightarrow \ …
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  • 4,058
6 votes
3 answers
426 views

Point-wise limit of finite valued functions

Let $X$ be a second countable topological vector space. Does there exist any sequence of finite valued functions $f_n\colon X\to X$ converging point-wise to the identity mapping on $X$?
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4 votes
1 answer
393 views

Separable Lindelöf locally convex spaces that are not second-countable

A Lindelöf space is a topological space in which every open cover has a countable subcover. Does there exists a Lindelöf locally convex space which is not second countable? I am also looking for a …
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3 votes
1 answer
272 views

A particular example of topological vector spaces

I am looking for a topological vector space $(X,\tau)$ enjoying the following conditions: 1- $(X,\tau)$ is not locally convex. 2- There exists a metric $d$ on $X$ and a sequence $\{X_n\}$ of subset …
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11 votes
3 answers
2k views

Is the strong operator topology metrizable?

Let $X$ be a separable Banach space. Is the strong operator topology metrizable on $B(X)$, the space of all bounded operators on $X$? SOT-$\lim T_i=0~$ if and only if $~\lim \|T_ix\|=0$ for every $x …
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