Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with weil-conjectures
Search options answers only
not deleted
user 66
6
votes
Are degrees of polynomials in Weil's zeta function equal/bounded to/by dimensions of SOME co...
The number of points always has an interpretation as a supertrace of Frobenius on the compactly supported cohomology, by the Grothendieck trace formula. The issue is that it can be quite difficult to …
- 44.7k
11
votes
Weil Conjectures for Grassmannians
Yes. Both cohomology and number of points are readily determined by looking at the Schubert cells (a cell of dimension k contributes one dimension to $H^{2k}$, and $q^k$ to the point count) and they …
- 44.7k
5
votes
Equivalent statements of the Riemann hypothesis in the Weil conjectures
I believe a consequence of the Riemann hypothesis in terms of number of points is that an n-dimensional smooth projective variety X will have $q^n+O(q^{n-1/2})$ points over $\mathbb{F}_q$, and the con …
- 44.7k