Search Results
| Search type | Search syntax |
|---|---|
| Tags | [tag] |
| Exact | "words here" |
| Author |
user:1234 user:me (yours) |
| Score |
score:3 (3+) score:0 (none) |
| Answers |
answers:3 (3+) answers:0 (none) isaccepted:yes hasaccepted:no inquestion:1234 |
| Views | views:250 |
| Code | code:"if (foo != bar)" |
| Sections |
title:apples body:"apples oranges" |
| URL | url:"*.example.com" |
| Saves | in:saves |
| Status |
closed:yes duplicate:no migrated:no wiki:no |
| Types |
is:question is:answer |
| Exclude |
-[tag] -apples |
| For more details on advanced search visit our help page | |
Results tagged with norms
Search options not deleted
user 61785
5
votes
Accepted
Sequence in *-algebra with different limits for two C*-norms?
Then
$$
\|a_i\|_1 = \|a_i-b\|_1 \leq \|a_i - b\|_2 \to 0
$$
So $(a_i)_i$ is convergent with respect to both norms and has limit $0$ in $\|\cdot\|_1$, but its limit in $\|\cdot\|_2$ is $b \neq 0$. …
- 3,768
10
votes
Accepted
Banach space with uncountable basis
I will pull together the comments into a community wiki answer with some of my own remarks so that the question isn't left on the unanswered questions list.
If you're willing to accept that it is cons …