Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 512834

For questions about the polylogarithm function, which is a generalization of the natural logarithm.

5 votes
3 answers
818 views

Conjectured closed form of $\int\limits_0^1 \frac{\ln y \operatorname{Li}_2 (-y)}{1-y^2} \, dy$

I uploaded this question here and here from my old account. Let $\psi^{(1)}$ be the trigamma function defined by \begin{equation} \tag{1} \psi_1(z) = -\int\limits_0^1 \frac{x^{z-1} \ln x}{1-x} \, dx. …
Martin.s's user avatar
  • 224
1 vote

Conjectured closed form of $\int\limits_0^1 \frac{\ln y \operatorname{Li}_2 (-y)}{1-y^2} \, dy$

Note section: \begin{align*} \begin{gathered} \therefore \sum_{n=0}^{\infty} \frac{(-1)^n H_n^{(2)}}{n^2}=-4 L i_4\left(\frac{1}{2}\right)+\frac{51}{16} \zeta(4)-\frac{7}{2} \ln (2) \zeta(3)+\ln ^2(2) …
Martin.s's user avatar
  • 224