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Forcing is a method first used to prove the continuum hypothesis is independent of the classical axioms of set theory

5 votes
2 answers
411 views

Question about prompt names of ordinals

So: The following concept is due to Shelah and I have some issues with a claim using this notion: Suppose that $\nu$ is a limit ordinal and that $P_\nu$ is an iteration of forcing notions. …
Stefan Hoffelner's user avatar
2 votes
1 answer
320 views

Gluing functions together in the generic extension

However a (probably very easy) question came up: Assume that we force with a Boolean algebra of the form $P(A) / I$, where $A$ is an arbitrary set and $I$ is an ideal over $A$; i.e. our forcing conditions …
Stefan Hoffelner's user avatar
8 votes
1 answer
466 views

Properness of quotient forcing

It is well known that if $P$ is a proper notion of forcing and $\Vdash_P \dot{Q} \text{ is proper}$ then the iteration $P \ast \dot{Q}$ is proper. … My intuition would tell me no, we could probably add in the first step a new stationary set, which gets killed after the second forcing. …
Stefan Hoffelner's user avatar
4 votes
2 answers
613 views

Examples of stationary set preserving forcings that are not semiproper?

A notion of forcing $P$ is called stationary set preserving iff each stationary subset of $\omega_1$ remains stationary in $V^P$. … It is standard to show that semiproper (and of course proper) notions of forcing are stationary set preserving. …
Stefan Hoffelner's user avatar
15 votes
0 answers
605 views

Cohen/Random reals over intermediate models in countable support iterations

I am also highly interested in the dual situation, where we replace Cohen forcing with Random forcing in the above. Can we guarantee that there is a real $r$ which is Random over all $V^{P_n}$'s? …
Stefan Hoffelner's user avatar
3 votes

Complexity of the statement 'P is proper'

I think that I might have found a solution to this rather dispensable question. I will sketch it: Consider the following characterization of properness: $P$ is proper iff for all $\lambda > 2^{|P|}$ …
Stefan Hoffelner's user avatar
3 votes
1 answer
583 views

Equivalent definitions of $(M,P)$-genericity

I started to read the chapter 31 in Jechs book about proper forcing. … Jech gives the following definition: Let $(P,<)$ be a fixed notion of forcing, $\lambda > 2^{|P|}$ and let $M \prec (H_{\lambda}, \in, <, ..)$, where $H_{\lambda}$ is the set of all sets whose transitive …
Stefan Hoffelner's user avatar
8 votes

Size of stationary sets

There exists a stationary subset of $P_{\omega_1} (\omega_2)$ of size $\aleph_2$. This is a result of Baumgartner and you can find a proof for this here: Why is this set stationary? I don't dare to a …
Stefan Hoffelner's user avatar
3 votes
3 answers
448 views

Complexity of the statement 'P is proper'

Assume that $(P,\le)$ is a notion of forcing. …
Stefan Hoffelner's user avatar
5 votes

Examples of ZFC theorems proved via forcing

Later a more elementary proof was found, using no 'metamathematical' concepts as forcing or ultrapowers of the universe, similar to the history of the proofs of Silvers theorem. …
6 votes
1 answer
320 views

Elementary chains in forcing extensions of $M_1$

Now suppose that $\mathbb{P}$ is a forcing notion of size $< \delta$, which preserves $\omega_1$ and that $G$ is a generic filter for the forcing. … Note that the statement is true if $\mathbb{P}$ is just the trivial forcing, however I would be interested in the case when we collapse cardinals down to $\omega_1$. …
Stefan Hoffelner's user avatar
5 votes
1 answer
498 views

The closure of a generic ultrapower

Let $I$ be a normal ideal on $P_{\kappa} (\lambda)$. Let $V$ denote our ground model. Now we force with the $I$-positive sets, and if $G$ is the resulting generic filter, it can be shown that $G$ is a …
Stefan Hoffelner's user avatar
8 votes

What ccc forcings add a Suslin tree?

If we start with $L$ as our ground model then whenever $T$ is a Suslin tree, the forcing $\mathbb{P}_T$ which shoots a branch through $T$ will always introduce new Suslin trees. … Thus in $L$, $\mathbb{P}_T$ is an example of a forcing which has the ccc, adds Suslin trees and does not add a Cohen real. …
Stefan Hoffelner's user avatar
10 votes

Kunen's use of Countable Transitive Models

It is true that you can use Löwenheim Skolem to get a countable model $M$ of ZFC assuming $Con(ZFC)$. But to use Mostowski you need additionally the well foundedness of that model, which doesn't have …
Stefan Hoffelner's user avatar
6 votes
1 answer
268 views

$\omega_2$-sequence of Suslin trees

Is it possible to have an $\omega_2$-length sequence of ($\omega_1$-)Suslin trees such that if one builds the product of finitely many trees in that sequence, one ends up with a Suslin tree again? Th …
Stefan Hoffelner's user avatar

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