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Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
6
votes
Accepted
finite groups with faithful real two dimensional representation
Since it's not clear, I assume the question you're asking is the following. "Fix an $n\geq2$. Which finite groups have a faithful real $n$-dimensional representation? Equivalently, what are the finite …
3
votes
Accepted
Computing determinants of characters
If you know $\chi$ then you can write down $\det \chi$ using Newton's identities. This is simply the observation that one can express the determinant of a matrix $\rho(g)$ in terms of traces of powers …
6
votes
Accepted
Character fields and Clifford's theorem
I don't think there's any clear cut relationship. In particular, the inequality $e \ge [\mathbb Q(\eta) : K]$ needn't hold. For example, take $G=S_5$, $N=A_5$ and let $\chi$ be the unique irreducible …
2
votes
Accepted
A technical problem on the contragredient representation in the context of locally compact t...
This follows from two facts:
The complement $E_1^\perp$ of $E_1$ in $\tilde{E}$ is isomorphic to the contragredient of $E/E_1$.
If $V$ is admissible and nonzero then $\tilde{V}$ is nonzero (and admi …
6
votes
4
answers
2k
views
Getting the Weyl dimension formula geometrically
I'm reading Borel and Hirzebruch's "Characteristic Classes and Homogeneous Spaces, II" and at one point in the paper (Section 22.4) they obtain Weyl's dimension formula for an irrep of a semisimple co …
7
votes
Accepted
When are orbits of semisimple group representations closed?
There's some terminology here that might be helpful for a literature search: $v$ is said to be semisimple if $Gv$ is closed in $V$ and said to be nilpotent if $v\neq0$ and $Gv$ is not closed in $V\set …
5
votes
Permutation representation inner product
Here's another proof.
If $G$ acts transitively on $X$, then the permutation representation of $G$ is induced from the permutation representation of the stabilizer $S$ of an arbitrary point. As a resu …
11
votes
Accepted
T-bundles and the Borel-Weil-Bott theorem
I'm very skeptical about the possibility of getting the full Borel–Weil–Bott theorem just by studying $G/U \to G/B$. Probably the closest thing I can think of is Bott's original proof of his theorem, …
5
votes
Orthogonal subgroups of dual group
Lemma 2.1.3 in Rudin's Fourier Analysis on Groups does this for locally compact abelian $G$ and closed $H \leq G$. This might not the best reference (may be a bit too general for a CS readership?), bu …
5
votes
Accepted
why are all characters of the maximal torus in a Lie group weights?
"Easiest" depends on how you set things up: everything really hinges on how you want to identify $X^\ast(T)$ with $\mathbb Z^n$. It's probably cleanest if you don't work explicitly with $\mathbb Z^n$, …
22
votes
What is significant about the half-sum of positive roots?
This is actually a fairly deep question. Your suspicion that there may be multiple answers is correct, but there might be some surprising connections between seemingly unrelated answers. Let me give o …
14
votes
3
answers
3k
views
Are complex semisimple Lie groups matrix groups?
Actually, my question is a bit more specific: Does every complex semisimple Lie group $G$ admit a faithful finite-dimensional holomorphic representation? [As remarked by Brian Conrad, this is enough t …
5
votes
Is there a generalization of Borel-Weil-Bott theorem for not completely reducible vector bun...
I'm not aware of any generalization that is strong enough to compute the cohomology of such bundles completely, but you can at least use the Borel--Weil--Bott theorem to get some vanishing results. Th …
9
votes
Accepted
Closed orbits of complete flags in $\mathbb{C}^n$
The whole flag variety is definitely not a single $O(n)$-orbit. You can see this already in the case of $n=2$, where the flag variety is just $\mathbb P^1$, and there are two orbits: $\{\pm i\}$ and e …
3
votes
Kostant's theorem on principal 3-dimensional subalgebras
Is it true that the centralizer $Z_{\frak{g}}(\frak{a})=\{\xi\in\frak{g}:[\xi,\eta]= $0$ \text{ }\forall\eta\in\frak{a}\}$ is trivial (or equivalently, that the trivial one-dimensional representati …