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8
votes
Central isogeny, Shimura varieties and exceptional cases
You can find answers to your questions in: Deligne, Pierre:
Variétés de Shimura: interprétation modulaire, et techniques de construction de modèles canoniques. Automorphic forms, representations and L …
2
votes
Accepted
Quotienting $G(\mathbb{Q})_{+}$ by $G^{\text{sc}}(\mathbb{Q})$ and inner forms
The answer is Yes. We denote $K(G)=G({\mathbb Q})_+/\rho G^{\rm sc}({\mathbb Q})$.
We compute $K(G)$; see the corollary below.
It is clear from the corollary that $K(G)$ is canonically isomorphic to $ …
10
votes
1
answer
567
views
Does every Shimura variety contain a generic point defined over a number field?
This question is related to my previous question, to which I got a partial answer.
Consider the cyclotomic field $L={{\mathbb{Q}}}(\zeta_8)={{\mathbb{Q}}}(\sqrt{2},i)$, where $\zeta_8$ is a primitive …
11
votes
2
answers
646
views
Abelian variety with prescribed endomorphism ring
Consider the cyclotomic field $L={{\mathbb{Q}}}(\zeta_8)={{\mathbb{Q}}}(\sqrt{2},i)$, where $\zeta_8$ is a primitive 8-th root of unity. Let $\Lambda={{\mathbb{Z}}}[\zeta_8]$ denote the ring of integ …
0
votes
Accepted
Tangent spaces of an indecomposable family of abelian varieties (parametrized by a Hodge typ...
No. Here is a counter-example (I add details to my comment).
Let $F$ be a totally real number field.
Consider the group $G_0=R_{F/\mathbb{Q}}\mathrm{SL}_{2,F}$, then $G_0$ naturally embeds into $\ma …
8
votes
Accepted
Reflex fields of Shimura varieties
The answer depends on your definition of a Shimura pair $(G,X)$.
Look in Section 2.1 of Deligne's paper.
If you assume only axioms (2.1.1.1), (2.1.1.2) and (2.1.1.3), then any number field $F$ can o …
2
votes
Accepted
Subgroups of $Sp_{2g}$ giving rise to Shimura data
First question: No, these conditions are not sufficient. For details see: Deligne, Pierre, Variétés de Shimura: interprétation modulaire, et techniques de construction de modèles canoniques. (French …
7
votes
different Shimura data with common underlying group?
The question is essentially about ${\mathbf{R}}$-groups, so we shall assume that $G$ is defined over $\mathbf{R}$.
It is not true that for a given connected reductive ${\mathbf{R}}$-group $G$, there …