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Subtag of the [oa.operator-algebras] tag for questions about von Neumann algebras, that is, weak operator topology closed, unital, *-subalgebras of bounded operators on a Hilbert space.
3
votes
Accepted
Disintegration of von Neumann algebra
Suppose B is a trivial bundle whose fibers are type I2 factors and p is a constant section of B corresponding to some projection with 1-dimensional image. Projections with 1-dimensional image in a ty …
3
votes
Accepted
Endomorphism of a type $III_1$ factor
No. Take any automorphism in the Tomita-Takesaki modular flow of M.
It is well known that an automorphism in the modular flow is inner if and only if M is semifinite.
6
votes
Accepted
A non-commutative Radon-Nikodym derivative.
Such t_0 is unique if its support is at most p, where p is the support of ϕ.
Note that we can replace t_0 by pt_0p and the support of pt_0p is at most p.
Without this additional condition t_0 is high …
4
votes
Lifting surjective von Neumann algebra homomorphisms
Morphisms of von Neumann algebra have very nice properties.
More precisely, the kernel of a morphism f: M→N of von Neumann algebras is a σ-weakly closed two-sided ideal.
Such ideals are in bijective c …
3
votes
Topology of the "normal spectrum" of a commutative von Neumann algebra
If by a normal character you mean a normal morphism of C*-algebras A→C,
then every commutative von Neumann algebra canonically decomposes
as a product of its atomic and diffuse parts,
the atomic part …
4
votes
Accepted
Idempotent homomorphisms of von Neumann algebras
Yes. The kernel of F is an ultraweakly closed *-ideal of M generated by some central projection z.
M splits as a direct sum of zM and (1-z)M.
As a 2x2 matrix F has only two nonzero entries, one that …
3
votes
Comparison-like lemma
This follows from the reduction theory for von Neumann algebras (alias direct integral decomposition).
Any von Neumann algebra is a direct integral of factors (i.e., von Neumann algebras with a trivia …
3
votes
Accepted
$e\precsim f$ and $1-e\precsim 1-f$ imply $e\sim f$?
No. Take e=0 and 0 < f < 1 such that both f and 1−f are infinite, with (1−f)~1.
Then e≾f because 0≾f for any projection f.
Also 1−e≾1−f because 1≾1−f, which holds by definition of f.
4
votes
Why are ultraweak *-homomorphisms the `right' morphisms for von Neumann algebras (and say, n...
A von Neumann algebra is a $C^*$-algebra $A$ that admits a predual,
i.e., a Banach space $A_*$ such that there is an isomorphism $A\to(A_*)^*$.
A morphism of von Neumann algebras is a morphism of $C^ …
2
votes
Regarding Haagerup $L^{P}$ spaces
How the norm on L^{P} space related to weight φ?
The L^p-spaces and their norms are independent of the choice of the weight φ.
See, for instance, the exposition by Yamagami in “Algebraic Aspects …
4
votes
Accepted
On existence of certain operators in von Neumann algebra
This is false.
Consider, for example, the case of M being the von Neumann algebra
of bounded complex-valued functions on an infinite countable set I.
It acts on the Hilbert space of square-summable fu …
6
votes
Accepted
Monoidal structures on von Neumann algebras
The category of von Neumann algebras W* admits a variety of monoidal structures of three distinct flavors.
(1) W* is complete and therefore you have a monoidal structure given by the categorical prod …
1
vote
Ideal of "Compact Operators" in a W*-algebra which gives the sigma-strong-* topology.
There is a notion of compact element for any W*-algebra,
namely, the two-sided ideal of compact elements is the norm-closure of the two-sided ideal
of finite-rank elements, the latter being defined as …
3
votes
Measurable functions and unbounded operators in von Neumann algebras
This question has at least 3 answers:
1) Given a von Neumann algebra M, take its canonical L^2-space L^2(M), which is a Hilbert space, take the corresponding canonical representation of M on L^2(M) vi …
12
votes
Accepted
Ideals in Factors
Blackadar in his textbook on operator algebras gives a complete classification of norm-closed ideals in factors.
See Proposition III.1.7.11.