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Homotopy theory, homological algebra, algebraic treatments of manifolds.
38
votes
Accepted
Simply-connected rational homology spheres
In dimension 4, we have the following:
Simply-connectedness implies that $H_1(M)=0$. The condition that $M$ be a rational homology sphere implies that $H_2(M), H_3(M)$ are finitely generated torsion g …
37
votes
Accepted
If $\Omega X \simeq \Omega Y$ then is $X \simeq Y$ for $X,Y$ simply connected?
To expand on my comment: As written (i.e. without requiring a map $f:X\to Y$), this is false in general. For an example, write $S^2$ as homogeneous space, $S^2=SU(2)/U(1)$. This exhibits $S^2$ as the …
32
votes
Accepted
What is the group of pointed homotopy classes of maps from $S^3 \times S^3$ to $S^3$?
We have that $S^3 \simeq \Omega \mathbb{H}P^{\infty}$, so by adjointness we can as well consider the group of maps $[\Sigma S^3 \times S^3, \mathbb{H}P^{\infty}]$. It is well-known that $[X,\Omega Y] …
24
votes
Accepted
Does the isomorphic of the fundamental groups imply the existence of a mapping inducing an i...
No and no. For an explicit counterexample to 1. (which is also a counterexample to 2.) take the map $\mathbb{R}P^2\to \mathbb{R}P^{\infty}$.
22
votes
Accepted
Is $[X, \_]$ a homology theory?
This holds only for compact objects (i.e. finite CW spectra), since it is easy to see that additivity fails otherwise (the other axioms of homology theories are satisfied). The usual way to obtain a h …
20
votes
1
answer
2k
views
Are there any cool applications of the generalized Atiyah-Hirzebruch(-Serre) spectral sequence?
Both the Atiyah-Hirzebruch and the Serre spectral sequence can be constructed from a skeletal filtration of a CW-complex:
We can construct the Atiyah-Hirzebruch spectral sequence by filtering $X$ by …
18
votes
Accepted
Is $SU(3)/SO(3)$ cobordant with a mapping torus?
The mapping torus $T$ of the complex-conjugation-map $\mathbb{C}P^2 \rightarrow \mathbb{C}P^2$ does the job.
For example by running the Serre spectral sequence with local coefficients, you obtain th …
16
votes
What is the first interesting matric Toda bracket in the stable homotopy of the sphere?
I know this post is quite old, but in case you are still interested, or anyone else is, I thought about sharing my recent thoughts about the topic. After all, this is the second result on "matric toda …
16
votes
Which singular homology classes can be represented by embedded manifolds?
The question in the title differs from the question spelled out in the post: In the title, you ask for embedded manifolds, in the post you ask for just maps from manifolds. I think the version of the …
15
votes
Accepted
Hairy ball theorem for odd-dimensional spheres
The Lefschetz fixed point theorem implies that any $f: S^n \to S^n$ without fixed points has degree $(-1)^{n+1}$. But an even map $S^n \to S^n$ has even degree, since it factors as
$$
S^n \xrightarrow …
15
votes
Accepted
Identifying two definitions of orientation on a vector space
Here's a direct way to relate the two:
One more structure is additivity of orientations. For $V, W$ of dimensions $n,m$, we have a canonical pairing
$$
\Lambda^n V \otimes \Lambda^m W \cong \Lambda^{n …
14
votes
Accepted
loop space of a finite CW-complex
This is true for finite $\pi_1$ and false for infinite $\pi_1$: Let $\widetilde{X}$ denote the universal cover of $X$, then $\Omega\widetilde{X}$ is the unit connected component of $\Omega X$, and $\O …
14
votes
Simplest example of non-trivial Toda bracket in spaces
The definition you've most likely encountered is the following:
For maps $W\xrightarrow{f} X \xrightarrow{g} Y \xrightarrow{h} Z$, such that adjacent maps compose to $0$, $g$ extends to a map on th …
14
votes
Accepted
Why are ordinary spheres not strictly invertible?
An $E_{\infty}$ structure extending the $E_1$ structure on $R(n)$ in particular yields maps $(\mathbb{S}^{2n})^{\otimes p}_{hC_p} \to \mathbb{S}^{2pn}$ splitting the inclusion of the bottom cell. The …
14
votes
Homology equivalence and isomorphism on $\pi_1$ not enough for homotopy equivalence?
This is a modification of Anders's suggestion:
Take $X=M(\mathbb{Z}[\frac{1}{2}],2)$ to be the Moore space with $H_2(X) = \mathbb{Z}[\frac{1}{2}]$. We can have $\mathbb{Z}/2$ act on $X$ this by a sig …