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Commutative rings, modules, ideals, homological algebra, computational aspects, invariant theory, connections to algebraic geometry and combinatorics.
6
votes
Accepted
Equi-dimensionality of special fibers in a flat family
It must be set-theoretically equidimensional, but not scheme-theoretically. (Consider two lines in space colliding, developing an embedded point at the intersection.)
For the positive statement, let …
4
votes
Accepted
Flat family: limit of intersection vs intersection of limits
Obviously $\widetilde{B_1} \cap \widetilde{B_2} \subseteq \widetilde{B_1\cap B_2}$. I'll discuss a sufficient condition for the reverse.
If $B_1\cap B_2$ is equidimensional, then so is $\widetilde{B_ …
2
votes
Uniqueness of a closed subscheme in a disjoint union
Equivalently, does $C$ have a subscheme $C'$ such that $p_C - p_{C'}$ is finite?
$C$ satisfies Serre's condition S1 iff $C$ is the closure of the union of the generic points of its geometric componen …
7
votes
Interpretation of multiplicity of a point
I think more fundamental and interesting than the notion of "multiplicity" is the notion of "tangent cone". Given $x \in X = Spec \ R$ defined by an ideal $I$, it's an interesting fact that $I^\infty$ …
2
votes
Cohen-Macaulay property for reducible schemes
(3) is nonsensical. For schemes of dimension $>0$, CM implies S1 which means no embedded components, like you were suggesting $X\cap Y$ to have.
(4) is true. A subscheme of affine space is a union of …
3
votes
Is the ideal of a closure of a Bruhat cell generated by generalized minors?
Exactly as Alexander said, this will fail for $G/P$ nonminuscule. The smallest example is the closed orbit $SO(5)/P$ of $SO(5)$ acting on ${\mathbb P}({\mathbb C}^4)$. The $T$-weight diagram of this r …
33
votes
2
answers
2k
views
If a field extension gives affine space, was it already affine space?
Let $R$ be a commutative Noetherian $F$-algebra, where $F$ is a
field (perfect, say). Assume that $R \otimes_F \overline F$ is a polynomial ring over the
algebraic closure $\overline F$.
Does it fo …
13
votes
2
answers
615
views
Computing intersection of subrings
Let $R$ be a finitely generated commutative ring over a field, for concreteness.
If $S,T \leq R$ are two finitely generated subrings, is their intersection
also finitely generated?
(Certainly …
5
votes
Rational powers of ideals in Noetherian rings
I give some hints about computing them in my paper Balanced normal cones and Fulton-MacPherson's intersection theory, section 3. (Also I compute 14 examples.)
I find it kind of astounding that this e …
13
votes
Is being reduced a generic property of schemes?
There's an exercise in [Eisenbud] that says that reducedness is R0 + S1, i.e. generic reducedness plus Serre's condition S1, which says that there are no embedded primes. This is analogous to normalit …
3
votes
Families of ideals with a given initial ideal
It's kinda gross, but it can be done.
To each monomial, add a generic linear combination of all smaller monomials (w.r.t. your term order).
Now insist that what you have is a Gr\"obner basis. How do …
0
votes
Can a zerodivisor reduce both the depth and the dimension?
OOPS: As Sándor points out, I missed the assumption that the ring is local, in the following example of the wrong thing:
"Inside 3-space, glue together a plane $y=0$ transversely with a parabola
$z=0 …
7
votes
Accepted
Is there an algorithm to decide if an ideal contains monomials?
Computing colon ideals is pretty quick. You could colon out the
variables in order. If the ideal changes, record the variable that
worked, and go back to the beginning of the list.
Either you get to t …
3
votes
1
answer
216
views
Simple reference for valuative criterion of integrality?
I'd like to see a complete proof of the simplest version of the following rough statement: "If $f/g$ is a rational function on a reduced scheme ($g$ not a zero divisor), and $f/g$ doesn't have poles i …
10
votes
3
answers
1k
views
Can injective modules over R give non-injective sheaves over Spec R?
In [Hartshorne, III.3] he proves that injective modules over $R$ give flasque sheaves over $Spec\ R$. I presume that's because they don't give injective sheaves, and flasque is the consolation prize. …