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Questions about Kähler manifolds and Kähler metrics.
4
votes
Non Kähler blow-up of a Kähler manifold
When $Y$ is compact, the blow-up is always Kahler;
see e.g. Lemma 3.4 in this paper
(this is a generally known folklore theorem which we
had to use, and hence written down).
For $Y$ non-compact the …
4
votes
Accepted
Relation between kahler potential and Hermitian metric
The function $\psi:=\log(fh^{-1})$ satisfies $\partial\bar\partial \psi=0$, because $ \partial\bar\partial\log f=\partial\bar\partial\log h =\omega$.
Such functions are called pluriharmonic. Locally a …
6
votes
Accepted
All Kähler metrics on a complex manifold?
Let $M$ be a compact complex manifold. The set of Kahler metric on $M$ in a given Kahler class is parametrized by the set of positive volume forms with given integral, because (by Calabi-Yau theorem) …
4
votes
1
answer
197
views
CSC Kahler metrics on a blown-up torus
Let $T$ be a compact torus, and $X$ its blow-up
in a point (or in several points). It seems that
$X$ is K-stable for any Kahler form on $X$.
Is there a reference to this?
Also, what can we say a …
0
votes
are stable holomorphic bundles over compact Kähler manifolds simple?
It seems that the answer is very simple (and should have been known to Uhlenbeck-Yau). Let $E$ be a stable bundle, equipped with an Hermitian-Einstein metric and connection, and $End(E)$ its authomorp …
6
votes
Accepted
The de Rham complex of a quaternion-Kahler manifold
The fundamental 4-form on a quaternionic-Kahler manifold is closed and gives the same kind of decomposition as the Kahler form on a Kahler manifold. Reference: Bonan, Edmond, Sur l'algèbre extérieure …
19
votes
Accepted
Three-dimensional compact Kähler manifolds
The main obstruction to existence of Kahler metric (in addition to Lefschetz
SL(2)-action and Riemann-Hodge relations in cohomology)
is homotopy formality: the cohomology ring of a Kahler manifold is …
5
votes
“Logarithmic” form of Kodaira Embedding
Sure, you should assume that there are sufficiently many functions which grow polynomially. Here is an example of such a result.
THEOREM: Let $M$ be a Stein variety equipped with a Kahler metric
outsi …
5
votes
1
answer
456
views
Level set of convex and plurisubharmonic functions (Ricci curvature and other curvature cond...
Let $\phi$ be a stricly plurisubharmonic function on a domain in ${\Bbb C}^n$, and $S=\phi^{-1}(c)$ its level set. Consider $S$ as a Riemannian manifold equipped with a metric induced by $dd^c\phi$. I …
4
votes
Accepted
Hodge isometry sending the Kahler class to its opposite
It is impossible, because the birational (movable) nef cone is mapped to birational nef cone, where birational nef cone is a cone of all classes which are non-negative on all curves which move in fami …
5
votes
Condition for infinite dimensional complex manifold to be Kähler by pullback form
There are three definitions of infinite-dimensional complex manifolds: strong (existence of holomorphic charts), weak (abundance of holomorphic functions) and formal (vanishing of Nijenhuis tensor). T …
6
votes
First chern class of fibers of compact Kaehler algebraic variety
Does a nonsingular fibre $\pi^{−1}(z)$ has vanishing first Chern class?
Yes. Denote a regular fiber $Z$; then
$K_M|_ Z= det(N^*Z)\otimes K_Z= K_Z$
by adjunction formula. On the other hand,
$K_M …
6
votes
Accepted
Are the Kahler Identities for a Holomorphic Vector Bundle Actually Interesting?
They can be used to prove the vanishing theorems (and more). Kodaira-Nakano vanishing theorem and Kodaira embedding theorem follow from these identities. One proves that the difference of the $\partia …
10
votes
Accepted
Infinite dimensional Riemannian geometry
Lempert, László The Dolbeault complex in infinite dimensions. III. Sheaf cohomology in Banach spaces. Invent. Math. 142 (2000), no. 3, 579-603.
Lempert, László The Dolbeault complex in infinite dimen …
12
votes
Accepted
Is the deformation limit of Ricci-flat Kahler manifolds Kahler?
There are counterexamples: a Moishezon manifold, which has trivial canonical class and is birationally equivalent to a hyperkahler manifold,
is also deformationally equivalent to a hyperkaehler manif …