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(Co)chain complexes, abelian Categories, (pre)sheaves, (co)homology in various (possibly highly generalized) settings, spectra, derived functors, resolutions, spectral sequences, homotopy categories. Chain complexes in an abelian category form the heart of homological algebra.

51 votes
8 answers
7k views

Motivating the category of chain complexes

Let $R$ be a commutative ring. For awhile I have been trying to motivate to myself more fully the definition of and various structures on the category $\text{Ch}(R)$ of chain complexes of $R$-modules …
Qiaochu Yuan's user avatar
37 votes

Does module Hom commute with tensor product in the second variable?

You can think about tensor products as a kind of colimit; you're asking the hom functor $\text{Hom}_A(L, -)$ to commute with this colimit in the second variable, but usually the hom functor only commu …
Qiaochu Yuan's user avatar
30 votes

intuition for hochschild homology

Slogan: Hochschild homology is a (derived) categorification of the trace. This means the identity at the end of John Pardon's answer is a categorification of the identity $\text{tr}(AB) = \text{ …
Qiaochu Yuan's user avatar
26 votes

Why are injective modules more complicated than projective modules?

Injective modules are of course just projective modules in the opposite category, so it seems to me that the question really is "why is the opposite of a module category more complicated than a module …
25 votes
Accepted

Any group is a quotient of an acyclic group?

Acyclic groups must in particular have trivial abelianization, so all of their quotients must be perfect. This is the only obstruction; A.J. Berrick shows in The acyclic group dichotomy (which I just …
Qiaochu Yuan's user avatar
22 votes

is the tensor product of projective modules again projective?

Recall that $P$ is projective iff $\text{Hom}(P, -)$ is exact. We have $$\text{Hom}_{A_1 \otimes A_2}(P_1 \otimes P_2, -) \cong \text{Hom}_{A_1}(P_1, \text{Hom}_{A_2}(P_2, -))$$ and a composition of …
Qiaochu Yuan's user avatar
17 votes
Accepted

The isomorphism class of $\mathrm{Ext}^1_\mathbb{Z}(\mathbb{R}/\mathbb{Z},\mathbb{Z})$

Writing $\mathbb{R}/\mathbb{Z} \cong \mathbb{Q}/\mathbb{Z} \oplus \bigoplus_I \mathbb{Q}$ where $I$ indexes a Hamel basis for $\mathbb{R}$ minus one element, we have $$\text{Ext}^1(\mathbb{R}/\mathbb{ …
Qiaochu Yuan's user avatar
15 votes

Dual of a bimodule

As explained in more detail in this blog post linked by Jakob in the comments, every $(A, B)$-bimodule $M$ has two natural duals: If $M$ is finitely generated projective as a left $A$-module, it has …
Qiaochu Yuan's user avatar
15 votes

Is every "nice" abelian category with enough projectives an additive presheaf category?

The category $[C^{op}, \text{Ab}]$ of $\text{Ab}$-valued presheaves on any (small, for simplicity) $\text{Ab}$-enriched category is about as nice as it gets - locally finitely presentable, Grothendiec …
Qiaochu Yuan's user avatar
15 votes

Compact object and compact generator in a category

Part of the tricky thing about this circle of ideas is that several definitions are not equivalent in full generality but become equivalent with extra hypotheses. For example, a basic result about com …
Qiaochu Yuan's user avatar
13 votes
2 answers
906 views

Is there an analogue of the Lefschetz fixed point theorem for discrete dynamical systems?

Background/Motivation Let $(X, f)$ be a discrete dynamical system. For now, $X$ is just a set and $f$ is just a function $f : X \to X$. Suppose that $f^n$ has a finite number of fixed points for ev …
Qiaochu Yuan's user avatar
12 votes

origin of spectral sequences in algebraic topology

I'm not comfortable enough with spectral sequences to answer this question, but let me answer an easier version of this question with spectral sequences replaced by long exact sequences. In algebrai …
Qiaochu Yuan's user avatar
12 votes
Accepted

Free Objects in Functor Categories

$[C, \text{Ab}]$ admits a forgetful functor to $[\text{Ob}(C), \text{Set}]$ (where $\text{Ob}(C)$ denotes the category with the same objects as $C$ but no non-identity morphisms). This is a direct gen …
Qiaochu Yuan's user avatar
10 votes
Accepted

A 2-category of chain complexes, chain maps, and chain homotopies?

Part of the problem is that you're not using a convenient definition of chain homotopy. I'll use a differential going down in degree. Let $I$ be the interval object in the category of chain complexes; …
Qiaochu Yuan's user avatar
9 votes
3 answers
559 views

For G a Lie group, can I make sense of G/G as a derived manifold in a nice way?

The functor sending a smooth manifold $M$ to its de Rham algebra $\Omega^{\bullet}(M)$ does not send quotients by actions of Lie groups to invariant subalgebras. The example I have in mind is a connec …
Qiaochu Yuan's user avatar

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