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Linear representations of algebras and groups, Lie theory, associative algebras, multilinear algebra.
8
votes
1
answer
421
views
Branching laws for smooth representations
Let $E / F$ be a quadratic extension of nonarchimedean local fields (characteristic 0 if it matters), and $\pi$ an irreducible infinite-dimensional smooth representation of $GL_2(E)$. Let $B$ be the u …
6
votes
1
answer
129
views
Paramodular newvectors and twists
In the book Local Newforms for GSp(4), Roberts and Schmidt have defined a theory of "new vectors" for smooth representations of $GSp_4$ over a nonarchimedean local field $F$ with trivial central chara …
3
votes
Paramodular newvectors and twists
I've stumbled across an answer to this old question of mine so I'm going to answer it myself. The following paper:
Johnson-Leung, Jennifer; Roberts, Brooks, Twisting of paramodular vectors, Int. J. Nu …
7
votes
0
answers
276
views
Branching laws for orthogonal groups
Let $G = SO_5(\mathbf{Q}_p)$ be the split special orthogonal group over $\mathbf{Q}_p$, and $H \subset G$ the group $SO_4(\mathbf{Q}_p)$, embedded in the usual way as the stabiliser of an anisotropic …
12
votes
1
answer
304
views
For a spherical pair $(G, H)$, which $G$-representations appear in $k[G/H]$?
Let $G$ be a reductive algebraic group (over some alg. closed field $k$ of char 0), and $H$ a subgroup such that $(G, H)$ is spherical (i.e., the Borel $B$ of $G$ has an open orbit on $G/H$). Then $k[ …
12
votes
Accepted
Existence of Cartan subalgebra
This argument does not work because the Killing form is not generally positive definite, so the orthogonal of a subspace wrt the Killing form is not necessary a complement of the subspace.
4
votes
1
answer
180
views
New vectors for representations of GSp4 with nontrivial central character
Roberts and Schmidt have developed a theory of new vectors for generic irreducible smooth representations of $\operatorname{PGSp}_4(F)$ for $F$ a nonarchimedean local field, using the "paramodular sub …
3
votes
Accepted
New vectors for representations of GSp4 with nontrivial central character
I'm adding an answer to this very old question of mine, since someone just contacted me about it. The problem is rather comprehensively solved in this 2019 preprint of Taeko Okazaki:
Takeo Okazaki, L …
1
vote
Antiholomorphic cusp forms of negative weight
I am not entirely sure what Clozel is trying to do here. He doesn't make it terribly precise what he means, and as you yourself have realised, if you read the article literally it seems that one case …
7
votes
eigen forms of integer weights and multiplicative functions
Trivially not, for cardinality reasons. Any function from the set of prime powers to $\mathbf{Z}$ extends uniquely to a multiplicative function $\mathbf{Z} \to \mathbf{Z}$, and there are obviously unc …
4
votes
Accepted
On the Cartan decomposition of unitary group
Theorem: Let $G$ be a reductive algebraic group over a local field $F$, let $K$ be any maximal compact subgroup of $G(F)$, and let $Z = Z(G)$. Then $K \cap Z(F)$ is the unique maximal compact subgroup …
12
votes
Accepted
What is the relationship between (g,K)-module and Maass forms?
So you've seen that there are essentially three types of (g, K)-modules: finite-dimensional ones; principal series; and discrete series. The finite-dimensional ones don't interest us, since they are n …
6
votes
Accepted
$l$-adic representations from Shimura curves
Yes, this can be done. In recent years, Clozel, Harris, Taylor and others have shown how to attach Galois representations to sufficiently nice automorphic representations of $GL_n$ (for arbitrary $n$) …
3
votes
Jacquet module and Frobenius reciprocity
In general, all we can say from "general abstract nonsense" is that if $\sigma$ is a subrepresentation of $Ind_P^G(\pi)$, then $\pi$ is a quotient of $J_N(\sigma)$; but you don't immediately get any f …
2
votes
Accepted
Part of some generic representation is also generic?
Let $\pi$ be the irreducible generic unramified representation of $Sp(W) $ that is a subquotient of $Ind(\chi_1, \dots, \chi_n)$.
I think the key here is to realise that this does not exist for all …