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The Catalan numbers form the sequence of numbers starting 1,1,2,5,14,42,... with explicit formula $\frac{1}{n+1}\binom{2n}{n}$. It counts many combinatorial objects like planar binary trees, triangulations, noncrossing partitions, Dyck paths, etc. See https://oeis.org/A000108

16 votes
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A double grading of catalan numbers

It appears that the zeta map which I used to answer Vince Vatter's initial question and which I describe in my answer there, see also page 50 of Jim Haglund's book, indeed solves also this problem: A …
Christian Stump's user avatar
15 votes
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A family of words counted by the Catalan numbers

Below my modified answer containing a complete bijection between the above sequences and Dyck paths: Let $a = (a_1,\ldots,a_n)$ be a sequence of $n$ integers. $a$ satisfies Property $A$ if it satisfi …
Christian Stump's user avatar
10 votes
Accepted

What does the $q$-Catalan Numbers count?

As Vasu commented already: there is not "the" q-analogue of the Catalan numbers. And indeed, you're mixing two different here. Your first q-Catalan numbers defined by the $q$-binomials is MacMahon's …
Christian Stump's user avatar
8 votes

Intuition behind Hook Length Formula

Here is a bijection to Dyck paths (or to well-formed bracketings): Take a SYT of shape $2\times n$ (so it contains the numbers $\{1,\ldots,2n\}$, and we aim to form a word of $n$ up-steps (opening br …
Christian Stump's user avatar
5 votes

enumerative meaning of natural q-Catalan numbers

Another less known interpretation of MacMahon's $q$-Catalan numbers is $$\sum_{\pi \in \mathcal{S}_n(231)} q^{\operatorname{maj}(\pi) + \operatorname{imaj}(\pi)} = \frac{1}{[n+1]_q} \begin{bmatrix} 2 …
Christian Stump's user avatar
1 vote

Equidistribution of returns and height of first peak of Dyck paths

For future references: as we have discussed in this question, this also follows from the "zeta map" sending the bistatistic (area,bounce) to the bistatistic (dinv,area). For another definition and fur …
Christian Stump's user avatar