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Continuum theory, point-set topology, spaces with algebraic structure, foundations, dimension theory, local and global properties.

21 votes
Accepted

Example of fiber bundle that is not a fibration

$\newcommand{\RR}{\mathbb{R}} \newcommand{\To}{\longrightarrow} \newcommand{\id}{\mathrm{id}}$The example described in Tom Goodwillie's answer to a related mathoverflow question essentially solves thi …
Ricardo Andrade's user avatar
14 votes
2 answers
2k views

Well-pointed space which is not locally contractible

I am looking for an example of a well-pointed space in which no (sufficiently small) neighbourhood of the base-point is contractible. As usual, a well-pointed space is a pointed space in which the inc …
Ricardo Andrade's user avatar
9 votes
Accepted

Does there exist a space X whose suspension is homotopy equivalent to [0,1] rel ends but whe...

$\newcommand{\set}[1]{\lbrace #1 \rbrace}$I will assume that the notation $\Sigma X$ in the question denotes the unreduced suspension of the space $X$. Quick answer: The notion of homotopy equivalenc …
Ricardo Andrade's user avatar
5 votes

Does Euclidean space have a compact factor?

Here is a proof which uses only singular homology.$\newcommand{\RR}{\mathbb{R}}$$\newcommand{\ZZ}{\mathbb{Z}}$$\newcommand{\To}{\longrightarrow}$$\def\set#1{\lbrace#1\rbrace}$$\newcommand{\Xminusx}{X\ …
Ricardo Andrade's user avatar
3 votes

Homomorphisms of Topological Groups which are Automatically Fiber Bundles?

The following statement follows from results of Palais (see theorem 2.3.3 in "On the existence of slices for actions of non-compact Lie groups"). When $G$ is a Lie group, any principal $G$-bundle (in …
Ricardo Andrade's user avatar
3 votes
2 answers
711 views

Finitely cocomplete categories of compact Hausdorff spaces

Edit: Zhen Lin incisively observes in a comment below that the category of compact Hausdorff spaces is monadic over the category of sets, hence is cocomplete. That answers the first part of question 1 …
Ricardo Andrade's user avatar
1 vote
Accepted

Topological question about right-lifting property and the evaluation map

$\newcommand{\into}{\hookrightarrow}$It seems that if $Z$ has the indiscrete topology, then the evaluation map $ev_0 : Z^I \to Z$ has the right lifting property with respect to any map. That provides …
Ricardo Andrade's user avatar
0 votes

(Homotopy) Y ENR and contractible subset implies Y is a retract

Observe that any retract of $\newcommand{\RR}{\mathbb{R}} \RR^n$ is necessarily a closed subspace of $\RR^n$. Assuming this necessary condition, the answer to the question is affirmative. More precise …
Ricardo Andrade's user avatar