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Algebraic varieties, stacks, sheaves, schemes, moduli spaces, complex geometry, quantum cohomology.
29
votes
Accepted
Voevodsky's six functor formalism VS Lucas Mann's
There may be some confusion in this question about what exactly Voevodsky/Ayoub and Mann do, as they do very different things.
Mann's thesis constructs a formalism of six operations in the setting of …
25
votes
Why is the motivic category defined over the site of smooth schemes only?
It's worth noting first that smooth schemes are essentially the smallest possible category from which one can define the motivic homotopy category: to make sense of $\mathbb A^1$-homotopy and of the N …
18
votes
Accepted
Category of motivic spectra
Here's a direct link to the book by Hovey–Palmieri–Strickland.
The category of motivic spectra is known to satisfy the axioms of Definition 1.1.4 in the book when the base is a countable field of cha …
16
votes
Accepted
$BG$ the stack, $BG$ the simplicial presheaf
The two constructions are not quite equivalent. Let me write $\mathbf BG$ for the stack and $B_\bullet G$ for the simplicial scheme to better distinguish between them. There is a third relevant player …
16
votes
Can we define homotopy groups using Tannakian categories
There certainly is a notion of higher Tannakian category which would have meaningful higher homotopy groups. I'm not sure how much of the theory has been worked out already, but higher Tannakian duali …
15
votes
Accepted
Who proved the motivic 6-functor formalism?
My understanding is that Scholze was citing Gallauer for the universal property of the 6FF of motivic spectra (an unpublished result as far as I know), not for the existence of the 6FF. This result wa …
14
votes
Accepted
The vanishing of $MGL^{2n+i,n}(X)$; do spectra of smooth projective varieties generate $SH_{...
(1) is true if $char(k)=0$. This follows from a combination of results. First of all, it is true over any field that the spectrum $MGL$ is connective, which means that
$$MGL^{p,q}(X)=0$$
if $p>q+dim …
14
votes
Accepted
Perfect chain complexes
In modern language, one would say that $D_{qcoh}(-)$ is a sheaf of $(\infty,1)$-categories on the scheme $X$ (so "homotopy stack" = "sheaf of $(\infty,1)$-categories").
If $X$ is affine, or more gene …
13
votes
Accepted
If we replace the spectrally ringed space in the definition of a spectral scheme with an arb...
Yes, they are more general. This is in fact already the case with ordinary rings. Let's call a classically-ringed $\infty$-topos which is locally the Zariski $\infty$-topos of an affine scheme an $\in …
13
votes
What is the dual of the stable infinity category of perfect complex on smooth proper variety?
It is self-dual. In general the dual of a smooth proper $R$-linear $\infty$-category $C$ is always $C^{\operatorname{op}}$, but for a scheme $X$ we have $\operatorname{Perf}(X) = \operatorname{Perf}(X …
13
votes
What is the negative cyclic homology of a smooth projective variety?
There are conceptually simple definitions, but they require a more symmetric definition of Hochschild homology. The Hochschild homology of $X/k$ (with coefficients in $\mathcal O_X$) is the homology o …
11
votes
Accepted
A Kunneth formula for the etale cohomology of the product of ('simple') varieties over not (...
The only reference I know for Künneth theorems in this generality are SGA4 and SGA4.5. Specifically, SGA4 has theorems for étale cohomology with proper support (which hold in ridiculous generality), b …
11
votes
Accepted
Derived version of equivalence between motives and representations of Motivic galois groups?
Let $k$ be a field and $\operatorname{DM}_{gm}(k)_{\mathbb Q}$ the ∞-category of rational geometric motives over $k$. A mixed Weil cohomology theory induces a symmetric monoidal exact functor
$$
R: \ …
11
votes
Accepted
How duality follows from a six functor formalism
Your description of the six functors does not mention any relations between the $!$-functors and the $*$-functors or the tensor product, which is where these dualities are hiding.
Poincaré duality is …
11
votes
Determinantal identities for perfect complexes
The formula also holds for perfect complexes. This can be deduced from the case of vector bundles, although it requires a lot of structure in that case. Namely, we need to use the fact that the determ …