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12 votes

Trigonometric inequality

I give a way that may work for odd numbers. This is too long for a comment. First, the quantity $$\cos\Big(\frac{2m\pi}{p}\Big)+\cos\Big(\frac{2n\pi}{q}\Big) = 2\cos\Big(\pi\Big(\frac{m}{p}+\frac{n}{ …
Christophe Leuridan's user avatar