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5
votes
2
answers
694
views
Zero tensor product over a complex algebra?
Let $A$ be an algebra over $\mathbb{C}$. Let $M$ be a left $A$-module, let $N$ be a right $A$-module and consider the tensor product $N \otimes_A M$, which is a complex vector space.
Q1: Can this ten …
6
votes
1
answer
1k
views
Tensor product of measure spaces
For a compact topological space $X$, denote by $\mathcal{M}(X)$ the Banach space of finite signed Borel (Radon) measures on $X$ with the total variation norm. This is canonically isometric to the dual …
4
votes
0
answers
182
views
Tensor product of bornological spaces and linear functionals
It is easy to see that the dual space of a bornological space $V$ (i.e. the space of bounded linear functionals) may be zero (just take any vector space with the power set as bornology). Hence in gene …
5
votes
0
answers
212
views
Tensors and Nuclear/Fredholm Operators
For a locally convex Hausdorff spaces $E$, consider the canonical map
$$\overline{\psi}:E^\prime \hat{\otimes}_\pi E \longrightarrow L(E_\sigma)$$
that maps the projective tensor product to the space …
6
votes
Accepted
Making the identification $\tau M\approx TM\oplus (TM\odot TM)$
Given a connection on the tangent bundle, you can define the second covariant derivative $\nabla^2f$ by
$$ \nabla^2f[X, Y] := \partial_X\partial_Y f - \partial_{\nabla_X Y} f.$$
Then $\nabla^2f$ is a …