Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options answers only not deleted user 14447
6 votes

Reading list for Equivariant Cohomology

I would like to point out that the term "equivariant cohomology'' is ambiguous. To those unfamiliar with modern algebraic topology, it means Borel cohomology, the cohomology theory that is the subjec …
Peter May's user avatar
  • 30.4k
4 votes

$RO(G)$-graded homotopy groups vs. Mackey functors

A. The brackets are the same computed in any model, as you say, and for most that entails fibrant approximation. For genuine $G$-spectra (complete universe), $G$ a compact Lie group, it goes back …
Peter May's user avatar
  • 30.4k
0 votes

Mackey(also Green and Tambara) functors and Greenlees-May

That is not what one expects from analogy with simpler structures. It would be of interest is to compute the ``box product'' $RV\Box RW$ in terms of the additive description of Mackey functors that …
Peter May's user avatar
  • 30.4k
14 votes
Accepted

Mackey(also Green and Tambara) functors and Greenlees-May

I thank you for the careful reading and apologize for the concision. This is a downwards induction on the size of subgroups. Using the explicit description of the $RV$ given top of page 239 and the c …
Peter May's user avatar
  • 30.4k
4 votes

Simple Equivariant homology [no borel-Moore]

I'm afraid this is not an easy subject to get into. There is no problem defining Bredon homology. Maybe first in print in a 1975 memoir of Soren Illman. A more recent summary is in my ``Equivariant …
Peter May's user avatar
  • 30.4k