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A detail in the proof of Schur's lemma: the closures of the $\mathcal{Ker}$ and $\mathcal{Im...
$\renewcommand\Im{\operatorname{\mathcal{Im}}}\newcommand\Ker{\operatorname{\mathcal{Ker}}}$I was sure that this is a trivial question and placed it on Math Stackexchange
https://math.stackexchange.co …
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