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Homotopy theory is an important sub-field of algebraic topology. It is mainly concerned with the properties and structures of spaces which are invariant under homotopy. Chief among these are the homotopy groups of spaces, specifically those of spheres. Homotopy theory includes a broad set of ideas and techniques, such as cohomology theories, spectra and stable homotopy theory, model categories, spectral sequences, and classifying spaces.

4 votes
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$\pi_1$ action on relative homotopy groups $\pi_n(X,A)$

I'd say the only tricky part is showing the action is well-defined, but if you trust it is here is a proof following Hatcher's proof for the basepointed version: Let's consider the general case of ma …
Connor Malin's user avatar
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6 votes
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Decomposable maps of half-smash products

No, take the case $X=\ast$. This asserts that any map $S^n \rightarrow Z \rtimes Y$ factors through the inclusion of a fiber $Z \rtimes \{y\}$, up to homotopy. This is certainly false, for instance if …
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1 vote
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Multi-simplicial generalization of $\Gamma$-spaces

The paper "Iterated monoidal categories" by Balteanu, Fiedorowicz, Schwanzl, Vogt gives an analogous result for functors $(\Delta ^{op})^n \rightarrow Top$ and n-fold loop spaces.
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7 votes
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Can a restriction of a null-homotopic spherical map be null-homopotic?

There exists nullhomotopic maps preserving codimension one equators such that the restriction to the equators is not nullhomotopic. Very easy examples come from taking non nullhomotopic maps of sphere …
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5 votes

Turning injection of homotopy groups to an isomorphism

Consider $i: S^1 \hookrightarrow M_f$ where $f:S^1 \rightarrow S^1$ is squaring and $M_f$ denotes the mapping cylinder. Then the inclusion induces a map $\pi_1(S^1) \rightarrow \pi_1(M_f)$ which has i …
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3 votes

Can one define relative Hurewicz maps using the Dold-Thom theorem

In the absolute case, $\pi_*(X) \rightarrow \pi_*(SP(X))$ can be identified with the Hurewicz map because one can explicitly compute $\mathbb{Z}=\pi_n(S^n) \rightarrow \pi_n(SP(S^n))=\mathbb{Z}$ and s …
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1 vote
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Preservation of fiberwise normal bundles under fiberwise homotopy equivalences

After looking at the actual construction of the fiberwise embedding of a bundle $M \rightarrow E \rightarrow B$ into $B \times \mathbb{R}^N$, it became clear how to adjust it to embed the mapping cyli …
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3 votes
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[M,N]≅ [M,R] ⊗ N for E-infinity modules

See page 70 of EKMM. The map $$F_R(M,N) \wedge_R F_R(M',N') \rightarrow F_R(M \wedge_R M', N \wedge_R N') $$ is an isomorphism if $M,M'$ are strongly dualizable or if $M$ is strongly dualizable and $N …
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9 votes
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Can a simply connected manifold satisfy $𝑀\simeq 𝑀\times 𝑀$?

Thanks to Dave Benson for pointing out an algebra error in the first draft of this answer and a missing detail. Suppose $X$ is homotopy equivalent to a finite dimensional, simply-connected, and noncon …
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13 votes

$\infty$-categorical description of $n$-manifolds

There is a specific "$\infty$-categorical" approximation of manifolds which your question seems to converge to. Before we address that, I would like to point out that Ayala-Francis do not classify exc …
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2 votes
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Cofibrancy of a right module over an operad

If $O$ is a reduced operad in $(C,\otimes)$, i.e. one with $O(\{*\})=1$ and $O(\emptyset)=*$, then under mild assumption on $(C,\otimes)$, the projective model structure exists on $\mathrm{RMod}_O$, i …
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31 votes
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If homotopy groups of spaces are identical, then stable ones are also identical?

No, a counterexample is the rational sphere $S^{2n}_\mathbb{Q}$ and $K(\mathbb{Q},2n) \times K(\mathbb{Q},4n-1)$. By the work of Serre these have the same homotopy groups, though it is easy to see the …
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0 votes

Does the bordism homology theory satisfy the weak equivalence axiom?

Thom directly constructed a natural isomorphism $MO_n(X) \rightarrow \pi_n (MO \wedge X_+)$ with no assumptions on $X$. The latter sends weak equivalences to isomorphisms since it is computed as a col …
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3 votes

Find a functorial zig-zag of spaces

If the diagrams $X_\bullet$ and $Y_\bullet$ are constructed canonically, but not necessarily naturally, from spaces $X,Y$ where $X \simeq Y$, one technique to construct such a zigzag is pick $f: X \si …
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4 votes
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Delooping a weak $E_1$ map by bar construction

No, take $Z$ a connected space for which $\Omega Z$ is homotopy commutative but $Z$ has no $A_\infty$ multiplication, e.g. $Z$ could be an $H$-space which doesn't have the homotopy type of a loop spac …
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