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Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.
3
votes
2
answers
296
views
Lie's third theorem via graded geometry
Lie's third theorem : Given any finite dimensional Lie algebra $\mathfrak{g}$, there exists a Lie group $G$ whose Lie algebra is equal to $\mathfrak{g}$.
In one of the talks, speaker mentions that thi …
4
votes
1
answer
319
views
Morphism of Lie algebras giving an action of Lie group on manifolds
Let $G$ be a Lie group and $\mathfrak{g}$ be its Lie algebra.
Let $ M$ be a manifold and $\mathfrak{X}(M)$ be its Lie algebra of vector fields on $M$.
Let $G\times M\rightarrow M$ be an action of t …
7
votes
1
answer
734
views
Differential forms of a Lie group giving cohomology of the Lie group
Consider a manifold $M$. Then, we have the notion of differential forms on $M$ and complex associated to that, denoted by $$\cdots\rightarrow \Omega^{k-1}(M)\rightarrow \Omega^k(M)\rightarrow \Omega^{ …
2
votes
0
answers
133
views
Associated bundle construction and classifying space
Let $\theta:G\rightarrow H$ be a morphism of Lie groups.
Given $G$ we have classifying space $BG$ and given $H$ we have classifying space $BH$. This $\theta:G\rightarrow H$ gives a map $B\theta:BG\ri …
2
votes
0
answers
154
views
Condition on a Lie groupoid to be represented by manifold/group or an action groupoid
Let $\mathcal{G}$ be a Lie groupoid. I am thinking of following questions.
When do we know $\mathcal{G}$ is weakly/Morita equivalent to a Lie groupoid of the form $(G\rightrightarrows *)$ for some …
4
votes
1
answer
234
views
Morphism of Lie groups $\theta:G\rightarrow H$ giving an equivalence of categories $BG\right...
Given a morphism of Lie groups $ \theta:G\rightarrow H$ and a principal $G$ bundle $ \pi:P\rightarrow M$ there are (at least) two ways to assign a principal $ H$ bundle.
See that the morphism of Li …
2
votes
2
answers
526
views
Fibered product of stacks comes from a Lie groupoid
I am adding some context here. I am reading Introduction to Differentiable Stacks by Gregory Ginot.
In page no $7$, just before the remark $2.2$ he says the following.
One shall be careful that f …
9
votes
6
answers
3k
views
Motivation for construction of associated fiber bundle from a principal bundle
Given a principal $G$ bundle $P(M,G)$ and a manifold $F$ with an action of $G$ on it from left, we construct a fiber bundle over $M$ with fiber $F$ and call this the associated fiber bundle for $P(M,G …
3
votes
3
answers
1k
views
Lie algebra bundle associated to a Lie group bundle
I was reading the paper Non abelian Differentiable gerbes (page 24) and came across notion of Lie algebra bundles associated to a Lie group bundle.
I am not comfortable with these notions and google …
4
votes
1
answer
506
views
Isotropy group of a Lie groupoid is a Lie group
I am trying to see that Isotropy group/object group/vertex group of a Lie groupoid is a Lie group.
Let $\mathcal{G}$ be a Lie groupoid and $x$ be an object in $\mathcal{G}$ i.e., $x\in \mathcal{G}_0 …
8
votes
5
answers
2k
views
What are Lie groupoids intuitively?
I am trying to understand about Lie groupoids but not able to get feeling for what it actually is.
So, question here is,
What are Lie groupoids? How similar are they to Lie groups, Groupoids and …