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Lie Groups are Groups that are additionally smooth manifolds such that the multiplication and the inverse maps are smooth.

3 votes
2 answers
296 views

Lie's third theorem via graded geometry

Lie's third theorem : Given any finite dimensional Lie algebra $\mathfrak{g}$, there exists a Lie group $G$ whose Lie algebra is equal to $\mathfrak{g}$. In one of the talks, speaker mentions that thi …
Praphulla Koushik's user avatar
4 votes
1 answer
319 views

Morphism of Lie algebras giving an action of Lie group on manifolds

Let $G$ be a Lie group and $\mathfrak{g}$ be its Lie algebra. Let $ M$ be a manifold and $\mathfrak{X}(M)$ be its Lie algebra of vector fields on $M$. Let $G\times M\rightarrow M$ be an action of t …
Praphulla Koushik's user avatar
7 votes
1 answer
734 views

Differential forms of a Lie group giving cohomology of the Lie group

Consider a manifold $M$. Then, we have the notion of differential forms on $M$ and complex associated to that, denoted by $$\cdots\rightarrow \Omega^{k-1}(M)\rightarrow \Omega^k(M)\rightarrow \Omega^{ …
Praphulla Koushik's user avatar
2 votes
0 answers
133 views

Associated bundle construction and classifying space

Let $\theta:G\rightarrow H$ be a morphism of Lie groups. Given $G$ we have classifying space $BG$ and given $H$ we have classifying space $BH$. This $\theta:G\rightarrow H$ gives a map $B\theta:BG\ri …
Praphulla Koushik's user avatar
2 votes
0 answers
154 views

Condition on a Lie groupoid to be represented by manifold/group or an action groupoid

Let $\mathcal{G}$ be a Lie groupoid. I am thinking of following questions. When do we know $\mathcal{G}$ is weakly/Morita equivalent to a Lie groupoid of the form $(G\rightrightarrows *)$ for some …
Praphulla Koushik's user avatar
4 votes
1 answer
234 views

Morphism of Lie groups $\theta:G\rightarrow H$ giving an equivalence of categories $BG\right...

Given a morphism of Lie groups $ \theta:G\rightarrow H$  and a principal $G$ bundle $ \pi:P\rightarrow M$ there are (at least) two ways to assign a principal $ H$ bundle. See that the morphism of Li …
Praphulla Koushik's user avatar
2 votes
2 answers
526 views

Fibered product of stacks comes from a Lie groupoid

I am adding some context here. I am reading Introduction to Differentiable Stacks by Gregory Ginot. In page no $7$, just before the remark $2.2$ he says the following. One shall be careful that f …
Praphulla Koushik's user avatar
9 votes
6 answers
3k views

Motivation for construction of associated fiber bundle from a principal bundle

Given a principal $G$ bundle $P(M,G)$ and a manifold $F$ with an action of $G$ on it from left, we construct a fiber bundle over $M$ with fiber $F$ and call this the associated fiber bundle for $P(M,G …
Praphulla Koushik's user avatar
3 votes
3 answers
1k views

Lie algebra bundle associated to a Lie group bundle

I was reading the paper Non abelian Differentiable gerbes (page 24) and came across notion of Lie algebra bundles associated to a Lie group bundle. I am not comfortable with these notions and google …
Praphulla Koushik's user avatar
4 votes
1 answer
506 views

Isotropy group of a Lie groupoid is a Lie group

I am trying to see that Isotropy group/object group/vertex group of a Lie groupoid is a Lie group. Let $\mathcal{G}$ be a Lie groupoid and $x$ be an object in $\mathcal{G}$ i.e., $x\in \mathcal{G}_0 …
Praphulla Koushik's user avatar
8 votes
5 answers
2k views

What are Lie groupoids intuitively?

I am trying to understand about Lie groupoids but not able to get feeling for what it actually is. So, question here is, What are Lie groupoids? How similar are they to Lie groups, Groupoids and …
Praphulla Koushik's user avatar