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This tag is used if a reference is needed in a paper or textbook on a specific result.

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Derived functors and functorial resolutions/(co)fibrant replacements

Let me expand on my comments. Functorial deformations for $\mathbf{K} (\mathcal{A})$ (the chain homotopy category) are much easier to obtain in practice than for $\textbf{Ch} (\mathcal{A})$ because K- …
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4 votes
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Does an indexed functor $C \rightarrow \mathbb{B}$ extend to $\operatorname{Psh}(C) \rightar...

There is definitely discussion of internal presheaves – the whole of section B2.5 is about them! In particular, the result you seek is Corollary 2.5.8: [Let $\mathcal{S}$ be a cartesian category with …
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4 votes
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Set theoretical foundations for derived categories

Fundamentally, working in NBG is not much different from working in ZFC, except that you are allowed one level of freedom to form collections of sets that are not themselves sets. As such, you still h …
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10 votes
1 answer
460 views

What does it mean for a category to be generated under (some) colimits?

This is going to be a long post, so let me state my question first and then explain what I am interested in by way of examples. Question. Is there any literature studying notions of generation under c …
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9 votes
0 answers
207 views

Is the category of all topological spaces, including the bad ones, simplicially tensored and...

Let $\textbf{Top}$ be the category of all topological spaces, including the bad ones. We can make $\textbf{Top}$ into a simplicially enriched category as follows: Given topological spaces $X$ and $Y$ …
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5 votes
1 answer
196 views

Schwänzl and Vogt, Cofibration and fibration structures in enriched categories

In [Schwänzl and Vogt, Strong cofibrations and fibrations in enriched categories], the authors refer to an earlier preprint, [Schwänzl and Vogt, Cofibration and fibration structures in enriched catego …
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6 votes
0 answers
652 views

Flat + locally of finite presentation + monomorphism = open immersion

It is known that the following are equivalent for an epimorphism $A \to B$ in $\mathbf{CRing}$: Let $S$ be the set of elements $a \in A$ such that $A [a^{-1}] \to B [a^{-1}]$ is an isomorphism. Then …
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17 votes
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Definition of ind-schemes

There is in fact no difference between the two definitions if you take your site to be the category of affine schemes – while it is true that the forgetful functor from sheaves to presheaves does not …
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6 votes
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Reference for constructing tensor products of finitely presented functors

This "tensor product" is also known as the weighted colimit in enriched category theory. The short answer is that all the isomorphisms you are interested in always exist, provided the objects you are …
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3 votes

Algebras for probability monad

The algebras for this monad can be described in essentially the same way: they are sets in which it makes sense to to take "convex combinations" of countably many elements. More precisely, an algebra …
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12 votes
0 answers
694 views

"To operate the machine, it is not necessary to raise the bonnet."

The quotation in the title is attributed to Frank Adams and appears in several places: In the preface of [2002, Operads in algebra, topology and physics]: "to operate the machine, it is not necessar …
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4 votes
2 answers
453 views

Aspheric functors and Grothendieck fibrations

Following Grothendieck, let us say that a category is aspheric if its nerve is weakly contractible and a functor $u : \mathcal{A} \to \mathcal{B}$ is aspheric if for every object $b$ in $\mathcal{B}$, …
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13 votes
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What's an initial object in a poset-enriched category?

There are several possible definitions of initial object in a 2-category $\mathfrak{K}$; which one is appropriate depends on your applications. A 2-category has an underlying ordinary category, so we …
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3 votes
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Groupoid as a 2-coequaliser

Your claim is incorrect because you truncated the simplicial diagram too much. Indeed, if what you said were true, then the isomorphism class of a group would be determined by its cardinality, but thi …
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9 votes
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Two definitions of modules in monoidal category

I will write $[B, C]$ instead of $\underline{\mathrm{Hom}}(B, C)$. Recall the tensor–hom adjunction: $$\mathrm{Hom}(A \otimes B, C) \cong \mathrm{Hom}(A, [B, C])$$ Thus there is a canonical bijection …
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