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1 vote

Robust generalization of matrix rank

The rank of a fuzzy matrix and its evaluation A new type of matrix rank, which is called margin rank in this article, is introduced to a fuzzy matrix defined to be rectangular array of fuzzy n …
Carlo Beenakker's user avatar
1 vote

Separating the spectrum of a Hermitian matrix

adding a nonzero $A$ will not change much; the degenerate eigenvalues of $A$ will split by an amount of order $\epsilon$ as a result of the perturbation by $\epsilon G$, which is already much larger than …
Carlo Beenakker's user avatar
2 votes
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Distribution of the spectrum of a perturbed matrix

Since $P(G)\propto{\rm exp}\bigl(-\frac{1}{2}{\rm Tr}\,GG^{\rm T}\bigr)$ is invariant under orthogonal transformations, if $A$ is real Hermitian you can work in a basis where $A$ is diagonal, with the …
Carlo Beenakker's user avatar