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7
votes
Accepted
Iterated ultrapowers of L
By Kanamori, ``The higher infinite'', Theorem 21.1 (due to Kunen), the existence of $0^\sharp$ is equivalent to the existence of an iterable $L-$ultrafilter.
Also note that if $j: L \to L$ is a non-t …
5
votes
Accepted
Are the failure of SCH and "$cf([\mu]^{cf (\mu)},\subset)>\mu^+$ for some singular" equicons...
As it is stated by Yair Hayut, in the comment above, statement $(1)$ implies statement $(2)$. Let's show that statement $(2)$ does not imply statement $(1)$.
Let $u(\kappa, \lambda)=cf(P_\kappa(\lam …
3
votes
Which large cardinals are upward reflecting?
As you are mainly interested in Shelah cardinals, let me add a few more remarks about them. Given a Shelah cardinal $\kappa$, let $wt(\kappa),$ the witnessing number of $\kappa,$ be the least $\lambda …
5
votes
"Bootstrapping" an unbounded class of inaccessible cardinals
If $\kappa$ is extendible, then there exists a proper class of inaccessible cardinals (and even more).
13
votes
Ordering of large cardinals by cardinality
Let me add one extra example that might be interesting.
Let $\pi_n^m$ and $\sigma_n^m$ denote respectively the least $\Pi_n^m$-indescribable and the least $\Sigma_n^m$-indescribable cardinal (if th …
4
votes
Wholeness Axiom and Ultimate L
I don't know to what extend the following answers your question, but a surprising result of Woodin says that the extension of the Inner Model Program to the level of one
supercompact cardinal must yi …
7
votes
1
answer
498
views
More on Kunen's inconsistency result
I would like to suggest another argument for Kunen's inconsistency result, and I wonder to know if the argument is correct. I am also interested to see, if the proof is correct, which part of the argu …
18
votes
Accepted
Large cardinal consistency strength and size
I may note that a cardinal of type $A$ may has more consistency strength of a cardinal of type $B$, while the smallest cardinal of type $A$ is smaller than the least cardinal of type $B$ (assuming car …
15
votes
Accepted
Strongest large cardinal axiom compatible with $V = L$?
Maybe a comment:
In the paper ``A large cardinal in the constructible universe'' Silver shows that if $\kappa\to (\alpha)^{<\aleph_0}$ for all countable $\alpha,$ then the same is true for $\kappa$ i …
6
votes
tree properties on $\omega_1$ and $\omega_2$
The answer to your question is yes. During the "IPM conference on set theory and model theory" James cummings gave me the basic idea of the proof of the following theorem:
Theorem. Assuming the exist …
12
votes
3
answers
1k
views
Necessary use of large cardinals in mathematics [duplicate]
There are some statements, whose consistency (or the consistency of their negation) require the existence of large cardinals (in the sense that if the statement (or its negation) is consistent, then i …
18
votes
What is the large cardinal strength of the assertion that every $\kappa$-complete filter on ...
Let us call a cardinal $\kappa, \kappa-$compact, if every $\kappa-$complete filter on $\kappa$ extends to a $\kappa-$complete ultrafilter.
The following is proved in Gitik's paper On measurable cardi …
5
votes
What are the known implications of "There exists a Reinhardt cardinal" in the theory "ZF + j"?
The following is due to Woodin:
Theorem. Assume $ZF$+ there exists a Reinhardt cardinal + there exists a proper class of supercompact cardinals is consistent.
Then there exists a genric extension of …
8
votes
Complete resolutions of GCH
Let me add more examples:
If we consider the global behavior of the power function, then we have for example:
(A) (Foreman-Woodin): $F$ can be such that $F(\alpha)>\alpha+\omega,$ all $\alpha$ ( …
3
votes
Questions about $\aleph_1-$closed forcing notions
The following results are obtained in a joint work with Yair Hayut and are now presented in our joint paper On Foreman's maximality principle:
Theorem 1. (Assuming the existence of a strong cardin …