Skip to main content
Search type Search syntax
Tags [tag]
Exact "words here"
Author user:1234
user:me (yours)
Score score:3 (3+)
score:0 (none)
Answers answers:3 (3+)
answers:0 (none)
isaccepted:yes
hasaccepted:no
inquestion:1234
Views views:250
Code code:"if (foo != bar)"
Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
Saves in:saves
Status closed:yes
duplicate:no
migrated:no
wiki:no
Types is:question
is:answer
Exclude -[tag]
-apples
For more details on advanced search visit our help page
Results tagged with
Search options not deleted user 10819

A manifold is a topological space that locally resembles Euclidean space near each point. More precisely, each point of an n-dimensional manifold has a neighbourhood that is homeomorphic to the Euclidean space of dimension n.

10 votes
Accepted

A senseful meaning of 'approximation of manifolds'?

The kind of approximation that one normally uses to prove something about topological manifolds is representing your manifold as an inverse limit of polyhedra (rather than smooth manifolds). … Whitney's embedding theorem applies only to smooth manifolds. …
Glorfindel's user avatar
  • 2,821
44 votes

Status of PL topology

some geometric topologists don't have a clue about regular neighborhoods, while others haven't heard of multijet transversality; but they all tend to be equally excited when it comes to Hilbert cube manifolds … Matveev, Algorithmic topology and classification of 3-manifolds 2D homotopy and combinatorial group theory Daverman-Venema, Embeddings in manifolds (about a third of the book is on PL embedding theory …
j.c.'s user avatar
  • 13.6k
18 votes

Status of PL topology

Some topologists, perhaps the majority, tend to think that smooth and topological manifolds are "present in nature" and are the genuine objects of study in geometric topology, while PL topology is a somewhat … ) and especially with Casson handles that occur in topological manifolds. …
Community's user avatar
  • 1
6 votes
Accepted

Do bistellar flips preserve shellability?

Obviously not, because there exist non-shellable combinatorial spheres, but any combinatorial $n$-sphere is bistellar-equivalent to the boundary of the $(n+1)$-simplex. The observation you mentioned …
Sergey Melikhov's user avatar
3 votes
2 answers
844 views

uniqueness of regular/tubular neighborhood with equivariant boundary

Let $N$ and $N'$ be regular neighborhoods of a subpolyhedron $P$ in a closed PL manifold $M$, and suppose that $t$ is a free PL involution on $M$ such that each of $\partial N$, $\partial N'$ is invar …
2 votes
Accepted

uniqueness of regular/tubular neighborhood with equivariant boundary

Akhmetiev that $S^6$ contains two smoothly embedded $5$-spheres invariant under the antipodal involution that are not equivariantly PL isotopic, and the reference is Lopez de Medrano's "Involutions on Manifolds
Sergey Melikhov's user avatar